Question

Exercise 31.13 - Enhanced - with Feedback You have a resistor of resistance 1902, an inductor of inductance 0.450 H, a capacitor of capacitance 6.40 pF and a voltage source that has a voltage amplitude of 26.0 V and an angular frequency of 300 rad/s. The resistor, inductor, capacitor, and voltage source are connected to form an L-R-C series circuit. Part A What is the impedance of the circuit? Express your answer in ohms. VOI ΑΣΦ FR ? Z= 12 Submit Request Answer Part B What is the current amplitude? Express your answer in amperes. EVO AEO ? 1 = A

Answer 1

Date Page Any Given- R = 19or La 0.450.H ,C=64 UF 300 rad. Is. V= 26 V t (A) Impedance for a LCR series circuit is a Z- R? + ( XL-Xc)2 = R²+ &c- X² ZE (1.90) + (Xc-X1) WXL Now, Reactive inductance (82) = XL = 300 x 01450 - 135 r of Reactive capacitance (c)2 1 wc 300x6:4X156 Xc= 106 520.83 r. 300 X 64 Thusi Za (90)2+ (520.03 135)2 Z 4301078 r free (32 current Amplitude (I) = v z 26 4301078 Thus i I 0.06 A

Xc>* Date Page (C) Tano I (XL-Xc or cOS 6 = R Z R Nooi O a cosy 190 4301078 078) Thusi $ = 63.78 Any (2) since ( xc 7 XL) Overall .. f circuit reactance source voltage * Confiv leads the current the As per HomeworkLib's guidlines; 9 can only attempt only 4 parts.