In the figure epsilon_0 = 15 V, R = 2.6 ohm, and L = 18 H....

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Answer 1

Answer #1

IN LR circuit the current builds as i = (E0/R*(1-e^-(tR/L))

R = resistance = 2.6 ohm

L = inductance = 18 H

t = 15 s

i = (15/2.6)*(1-e^-(15*2.6/18))

i = 5.1 A <<<---------------answer

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Answer 2

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