Question

What is the heat absorbed in kcal and kJ when 2.50 moles of NO are produced...

What is the heat absorbed in kcal and kJ when 2.50 moles of NO are produced from oxygen and nitrogen?

N2(g)+O2(g)→2NO(g)N2(g)+O2(g)→2NO(g)

ΔHΔH = +43.0 kcal/molO2kcal/molO2 or +180 kJ/molO2kJ/molO2

The following equation shows the conversion of aluminum oxide (from the ore bauxite) to aluminum:

2Al2O3(s) → 4Al(s)+3O2(g)2Al2O3(s) → 4Al(s)+3O2(g), ΔHΔH = +801 kcalkcal (+3350 kJkJ )

How many kilocalories are required to produce 1.15 molmol of aluminum?.

How many kilojoules are required to produce 1.15 molmol of aluminum?

How many kilocalories are required to produce 14.6 gg of aluminum?

How many kilojoules are required to produce 14.6 gg of aluminum?

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Answer #1

Answen 0 N2 (9) + 02 (3) ► 2009) (H = +43.0, Kcal/mol I mole of Ne realt with AH = +180 Kg/mol. Imole of oor mole of or produ1. n. 115 moles amount of when 4 moles of aluminium produces, the heat absor a required = 801 kcal. 0 115 moles of aluminium

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