Question

Dielectric constant k between two conductive boards with I lengths in square shape x between the parallel plates It is arranged. Assume that the dielectic fills the plates completely. a)Calculate the equivalent capacity. b) accepting the potential difference between the plates Find the energy stored by the capacitor. Türkce (Türkiye) buraya yazin a

Answer 1

For a simple capacitor capacity (C) = EoA d (A=1) d (L) For a dielectric filled capacitor (C) = k'e, A A area of square plates k'EL² d d distance between the plates. to - permittivity of free space k'- dielectric constant. Q=CV V = Q = Qd C k to L² Energy = 1 cv² = 1 b' to 1² v²

b Ez LE R, = 2 kr R2 = 3Rr R3 = 4 kr E = 70v Ez = GOV Ez = 80V Es Rz I e R f 0 - Ea + E2 + (1 - 12) R₂ + i, R, = 0 -70+60+ i, CR + R₂) -12 R₂ = 0 51-312 =10 - Ez + 1₂ R₂ + Ez + (iz-i) R₂ = 0 -60+80 + iz(R3+R₂) -2, R₂ = 0 Tiz-Bi=-20 3i, - 7i2=20 2 *5 151,-a iz=30 151, -3512 = 100 2612 = -70 12 = -2.69 mA 3 ;, = 20+7 iz i, = 0.39 m A. Potential difference betweed c and f = Ez + Rali,tia) = 60+ 3 (2.69+0-39) = 69.24 V

20 m - 69.24v b ) a. in (20115) + 93 2220 M 2005 b + 20+5 100 25 50 220 18 o (20115)+2 100 +2 2 b 25 Gr 8 CE 6 13 3 39 b U ㅗ ㅗ 9 & 3+ 6 + 9 54 Rp 18 Rp = 3 AN 3 Req = 8+3 = 12 b