Question

Assignment Gradebook ORION Downloadable eTextboolk ent Chapter 23, Problem 063 Your answer is partially correct. Try again. A proton at speed v-3.81 x 102 m/s orbits of radiusr-0.899 cm outside a charged sphere. Find the sphere's charge Number 1.5154E-15 the tolerance is +/-2% Click if you would like to Show Work for this question: ORen Show Work SHOW HINT LINK TO TEXT LINK TO SAMPLE PROBLEM uNK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM

Answer 1

Here Electrostatic force is balanced by centripetal force

Here Electrostatic force is balanced by centripetal force K Vertical-bar q Vertical-bar e/r^2 = mv^2/rVertical-bar q Vertical-bar = m v^2 r/K e = (1.67 times 10^-27) (3.81 times 10^2)^2 (0.899 times 10^-2)/(9 times 10^9) (1.6 times 10^-19)Vertical-bar q Vertical-bar = 1.5134 times 10^-15 C Here the force is inward, towards center of the sphere, The charge q must be negative, since proton is positively charged. Therefore q = -1.5134 times 10^-15 C

Here the force is inward ,towards center of the sphere ,The charge q must be negative ,since proton is positively charged.

Therefore