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An electron moves at 1.0 m/s perpendicularly across a 1.0 T (N/A m) magnetic field. What is the magnetic force exerted on thi
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Answer #1

F = qvB

q=1.6 x 10-19 C

v = 1 m/s

B = 1 T

Thus:

F = (1.6 x 10-19) x (1) X (1) = 1.6 x 10-19 N

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