Question

Given that the ionization constant for water (Kw) is 4.52x10-15 at 15 °C, calculate the pH for pure water at 15 °C Report your answer to 3 decimal places. 16.5

Not sure if this is right, pure water so its [H] squared

Kw = [H] squared so I square rooted and took the -log of this to get the pH

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Kw = [H+][OH-]

since water is neutral,

[H+] = [OH-]

So,

Kw = [H+][H+]

4.52*10^-15 = [H+]^2

[H+] = 6.72*10^-8 M

use:

pH = -log [H+]

= -log (6.72*10^-8)

= 7.1726

Answer: 7.173

Add a comment
Know the answer?
Add Answer to:
Not sure if this is right, pure water so its [H] squared Kw = [H] squared...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • for water (Kw) is 9.311 × 10-14 at 60 oC. Calculate the [H2O+], [OH-], pH, (8...

    for water (Kw) is 9.311 × 10-14 at 60 oC. Calculate the [H2O+], [OH-], pH, (8 pts.) The ionization constant and pOH for pure water at 60°C

  • number 16 15. Explain why a sample of pure water at 40 °C is neutral even...

    number 16 15. Explain why a sample of pure water at 40 °C is neutral even though [H3O= 1.7 x 101 1014 at 40 °C. M. Kw is 2.9 X 16. The ionization constant for water (Ky) is 2.9 x 1014 at 40 °C. Calculate [H30 ], [OH], pH, and pOH for pure water at 40 °C.

  • calculate equilibrium dissiociation constant of water help! We know that Kw = 1.0 x 10-14 at...

    calculate equilibrium dissiociation constant of water help! We know that Kw = 1.0 x 10-14 at 25°C. At 37°C, the [H3O+] in pure water is 1.6 x 10"| M. Calculate the equilibrium dissociation constant of water, Kw, at this temperature. A. 2.6 x 10-14 | CNH-TT H+7: 10 x 10-14 DH = -log(11 B. 1.0 x 10-7 C. 1.0 x 10-14 [1-6x10-?][6.16 *10-8] PH= 6.79 D. 1.6 x 10-7 POH=7. 21

  • 1- Calculating [H+] for Pure Water: In a certain acidic solution at 25 ∘C, [H+] is...

    1- Calculating [H+] for Pure Water: In a certain acidic solution at 25 ∘C, [H+] is 100 times greater than [OH −]. What is the value for [OH −] for the solution? In a certain acidic solution at 25 , [] is 100 times greater than [ ]. What is the value for [ ] for the solution? 1.0×10−8 M 1.0×10−7 M 1.0×10−6 M 1.0×10−2 M 1.0×10−9 M 2. ± Acid-Base Relationships in Water: Water ionizes by the equation H2O(l)⇌H+(aq)+OH−(aq)The...

  • pH operates off of a ___________ scale.                 The autoionization constant of water is abbreviated ________....

    pH operates off of a ___________ scale.                 The autoionization constant of water is abbreviated ________.                 The molar concentration of hydronium in pure water at 25ºC has been measured to be ________.                 The relationship between hydronium and hydroxide in any dilute aqueous solution is represented by _________.                 The p in pH stands for _________.                 The relationship between pH and pOH is ___________.                 The pH value of a 1 M solution of strong acid would be...

  • Couldn't get the answer no matter what...Please make sure you get it right, so I can...

    Couldn't get the answer no matter what...Please make sure you get it right, so I can give you a thumbs up! 14. + 0/1 points Previous Answers OSUniPhys1 13.4.P.040. My Notes Ask Your Teacher For the following questions, use the data found in Appendix D. /kg in your calculations. Round your answer to at least four significant figures.) Calculate the mass (in kg) of the Sun based on data for Saturn's orbit. (Use G = 6.67 x 10-11 N.m 1.986e30...

  • please help me solve this, i only get ONE try so please please make sure the...

    please help me solve this, i only get ONE try so please please make sure the answer is right, thanks!! O KINETICS AND EQUILIBRIUM Deducing a rate law from initial reaction rate data Some measurements of the initial rate of a certain reaction are given in the table below. H2 initial rate of reaction 53.0 m/s 1.28 M 1.28 M 0.130 M L2] 2.30 M 0.284 M 2.30 M 6.54 M/s 5.38 MIS Use this information to write a rate...

  • * Im not actually sure if i got these right but really not sure about the bottom questions gender selection, the pr...

    * Im not actually sure if i got these right but really not sure about the bottom questions gender selection, the proportion of baby girls is less than 0.5. 1 standard deviation below 0. Complete parts (a) through (h) A 0.01 significance level is used for a hypothesis test of the claim that when parents use partic ular method Assume that sample data consists of 36 girls in 81 births, so the sample statistic of a below Click here to...

  • need help with 7 and 8. also did I do number nine right? • Write the...

    need help with 7 and 8. also did I do number nine right? • Write the ionization cautions for the dissociation of the diprotic acid, H,C,04. called oxalic acid. The following dissociation consta owing dissociation constants were located on a scrap piece of paper near the bottle of oxalic acid in the chemical room: 6.40 X 10 and 5.91 X 102. Assign cach equation you have written one of these values and explain your reasoning. H₂C₂O4 8. Given the K,...

  • RUVILUULI Q. #1. The equilibrium constant for the auto-ionization of water 2H30 (I) = H3O'(aq) +...

    RUVILUULI Q. #1. The equilibrium constant for the auto-ionization of water 2H30 (I) = H3O'(aq) + OH(aq) is 1.0 x 10-4 at 25°C and 3.8 x 10-14 at 40°C. Is the forward process endothermic or exothermic? Need to show your calculation. Ans: exothermic Q. #2. If you have 0.040 M solution two strong acids like HCI and H2SO, which one do you think would have behaves as stronger acids? Explain your answer with ICE table and relevant calculation. K for...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT