Find AHrxn for: C2H2(g) → 2C(s) + H2(g) given the following information: C2H2(g) + 5/2 O2(g)...
loab beboo 2CO2 + H2O. 7. Calculate AH for C2H2 +5/202 Given C(s) +O2(g) CO2(g) AH = -393.5 kJ H2+½ O2 H2O AH= -285.8 kJ 2C+H2 C2H2 AH = 226.8 kJ 008700000 08.0 Lon Qoe cOeEo.O60
3. Given the following data: C2H2 (8) +5/2O2(g) → 2CO2 (g) + H20 (1) = - 1300. KJ C(s) + O2(g) → CO2 (g) = -394 kJ H2(g) + 1/2O2(g) → H20 (1) = -286 kJ Calculate for the reaction 2C(s) + H2(g) → C2H2 (8)
Hess's Law Given the following data: C2H2(g) + 5/202(9) + 2002/9) + H20(1) AH' = -1300.0 kJ CO2(g) + C(s) + O2(g) AH° = 393.5 kJ 2C(s) + H2(g) C2H2(g) AH° = 227.0 kJ Calculate AH for the reaction H2(g) + 1/202(9) — H20(1) Submit Answer Tries 0/5
Given the following equations and AH' values: C(s) + O2(g) + CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) - H20 (1) AH = -285.8 kJ 2C2H2 (8) + 5O2(g) + 4CO2(g) + 2H20 (1) AH'= -2598 kJ Determine the heat of reaction (in kJ) at 298 K for the reaction: 2C(s) + H2(8) C2H2 (8) 0-136.8 0-219.8 0-109.9 O-167.1 +226.2
Consider the following data. 2 C(s) + H2(g) C2H2(g) H = +226.8 kJ CO2(g) C(s) + O2(g) H = +393.5 kJ 2 H2O(l) 2 H2(g) + O2(g) H = +571.7 kJ Use Hess's law to calculate H for the reaction below. 2 C2H2(g) + 5 O2(g) 4 CO2(g) + 2 H2O(l) find kJ
DaC. NUL20 1) Find AH, for the reaction 2H2(g) + 2C(s) + O2(g) → C2H5OH(I), using the following thermochemical data. For Hess's Law, rewrite equations to find out AH. C2H5OH (1) +2 02 (g) → 2 CO2 (g) + 3H20 (1) AH = -875.J C(s) + O2(g) → CO2 (g) AH = -394,51 kJ H2(g) + 12 02 (g) → H20 (1) AH = -285.8 kJ
Enter your answer in the provided box. Calculate AHrxn for Ca(s)1/2 O2(g) +CO2(g) -» C2CO3(s) given the following set of reactions: Ca(s)1/2 O2(g)CaO(s) AH635.1 kJ = CaO(s) CO2(g) СаСО3(9) AH= 178.3 kJ kJ
1. Calculate the change in enthalpy for this reaction: 2C(s) + H2(g) → C2H2(g) Given the following AHo -1299.5 kJ HP =-393.5 kJ HP -285.8 kJ CHI2(g) + (5/2)O2(g) → 2CO2(g) + H2O(1) C(s) + O2(g) → CO2(g) H2(g) + (12)O2(g) → H2O(1) A balloon contains 0.45 g of carbon dioxide and 0.6 grams of helium at 1.1 bar. If you compress the container to 80%ofits original volume, what will be the final pressure? Half a liter of water is...
From the following data, C(graphite) + O2(g) → CO2(g) AHrxn = -393.5 kJ/mol H2(g) + O2(g) → H200) AH"rxn = -285.8 kJ/mol 2C2H6(g) + 702(g) -> 4CO2(g) + 6H2O(l) Arxn=-3119.6 kJ/mol Calculate the enthalpy change for the reaction: 2 C(graphite) + 3H2(g) + C2H668)
5. Using standard heats of formation, calculate AH for 4 FeO (s) + O2(g) → 2 Fe2O3 (s) AH1 of FeO (s) = -272.0 kJ/mol AHºf of Fe2O3 (s) = -825.5 kJ/mol 3. Given 3 C (s) + 4 H2(g) → C3H8 (9) AH = -103.85 kJ/mol C(s) + O2(g) + CO2(g) AH = -393.5 kJ/mol H2 (g) + 12 O2(g) → H2O (1) AH = -285.8 kJ/mol find AH for C3H8 (g) + 5 O2(g) → 3 CO2 (g)...