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ection 3-6. A shaft driven by an electrical motor is used to rotate an impeller. The conn between the shaft and the impeller
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Answer #1

Let's first find the shear stress, (\tau):

\tau = \frac{Force}{Area}

\tau = \frac{Force needed to rotate the impeller}{Area under shear}

\tau = \frac{5000N}{\pi r^{2}}

\tau = \frac{5000N}{\pi (5*10^{-3})^{2}} (Given Diameter of fillet= 10mm i.e. radius in meters =5x10-3

\tau = 63.66MPa

Hence, as the obtained shear stress is less than the shear strength which is 400MPa, Hence the fillet will not go under shear yielding.

Now,

Given factor of safety is 4,

i.e 4\tau = 4*63.66= 254.64MPa (Given shear strength of the cylindrical fillet = 400MPa)

As shear strength of the fillet is more than 254.64MPa, Hence at the factor of safety 4, the fillet is still strong enough to prevent shear yielding.

Now,

As we know that sharp edges and corners are the sites for highest stress development during fatigue loading. Moreover, in our case, the design does not consider this fatigue loading condition. Hence it would be better to go for rounded corners to prevent fatigue failure of the fillet, impeller, and shaft under fatigue loading.

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