When 3.44g of the mineral gypsum, CaSO4⋅xH2O, is heated to 128∘C, 2.90g of CaSO4⋅1/2H2O is obtained.
What is the value of x in the formula of gypsum?
If you heat up the material CaSO4 * xH2O,
the mass decreases by 3.44 g - 2.90 g = 0.54 g which is water.
0.54 g = 0.02997 moles water
CaSO4 * 1/2H2O has a molecular weight of 145.15 g/mole
2.9 g is then 0.01998 mole
Divide both by 0.01998
CuSO4 * 1/2H2O = 0.01998 mole/0.01998 mole = 1 mole
0.02997 mole / 0.01998 mole = 1.5
So, in heating up the CuSO4 * 1/2H2O the relative amount of water
given off is 1.5 moles. Since there is still 0.5 moles of H2O left
bound to the CuSO4, the original material was
CaSO4 * 2H2O
x = 2
When 3.44g of the mineral gypsum, CaSO4⋅xH2O, is heated to 128∘C, 2.90g of CaSO4⋅1/2H2O is obtained....
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