Question

add 1 + 2 + 3 + 4 + .... + 1,000,000 = ?

then add 1,000,000 + 999,999 + 999,998 + ... + 4 + 3 + 2 + 1 = ?

are they the same?

then repeat this with double floating point using 100 billion

Please Program this in PYTHON

Answer 1

The explanation is done in the code itself. If you have any queries write a comment. If you have understood upvote. Thank you

SOLUTION:

##sum from 1 to 1000000
sum1=0
##sum from 1000000 to 1
sum2=0

##iterate from 1 to 1000000 and calculate sum
for i in range(1000000+1):
sum1=sum1+i
##print sum
print("Sum from 1 to 1000000 ",sum1)
##iterate from 1000000 to 1 and calculate sum
for i in range(1000000,0,-1):
sum2=sum2+i
##print sum
print("Sum from 1000000 to 1 ",sum2)

if(sum1==sum2):
print("Both are same ")
else:
print("Both are not same")
##variable to store
sumOfFloat=0.0
sumOfFloatreverse=0.0
number=1
##calculating the number by adding 0.1 every time till
while(number<=1000000):
sumOfFloat=sumOfFloat+number
number=number+0.1
print("Double floating point from 1 to 1000000 ",sumOfFloat)
number=1000000
##calculating the number by substracting the 0.5 every time and checking
while(number>=1):
sumOfFloatreverse=sumOfFloatreverse+number
number=number-0.1
print("Double floating point from 1000000 to 1",sumOfFloatreverse)
##check for equality
if(sumOfFloat==sumOfFloatreverse):
print("Both are same ")
else:
print("Both are not same")

CODE IMAGE:

sum.py - C:/Users/vinod/AppData/Local/Programs/Python/Python37-32/sum.py (3.7.2) File Edit Format Run Options Window Help ##sum from 1 to 1000000 suml-0 ##sum from 1000000 to 1 sum2-0 iterate from l to 1000000 and calculate sum for i in range (1000000+1) suml-suml+i ##print sum print("Sum from 1 to iterate from 1000000 to 1 and calculate sum 1000000 ",suml) for i in range (1000000,0,-1) sum2=sum2+i #print sum print ("Sum from 1000000 to i ",sum2) if (suml-sum2) print ("Both are same ") else: print ("Both are not same") ##variable to store sumOfFloat=0.0 sumOfFloatreverse- 0.0 number-l ##calculating the number by adding 0.1 while (number< -1000000) sumOfFloat-sumOf Float+number every time till number-number+0.1 print ("Double floating point from l to 1000000 number 1000000 calculating the number by substracting the 0.5 every time and checking while (number> 1 ) sumofFloatreverse -sumOfFloatreverse+number ', sumOfFloat) number-number-0.1 print ("Double floating point from 1000000 to l",sumOfFloatreverse) #check for equality if (sumOfFloat-= sumOfFloatreverse) print ("Both are same ") else: print ("Both are not same")

OUTPUT:

sum.py - C:/Users/vinod/AppData/Local/Programs/Python/Python37-32/sum.py (3.7.2) File Edit Format Run Options Window Help ##sum from 1 to 1000000 suml-0 ##sum from 1000000 to 1 sum2-0 iterate from l to 1000000 and calculate sum for i in range (1000000+1) suml-suml+i ##print sum print("Sum from 1 to iterate from 1000000 to 1 and calculate sum 1000000 ",suml) for i in range (1000000,0,-1) sum2=sum2+i #print sum print ("Sum from 1000000 to i ",sum2) if (suml-sum2) print ("Both are same ") else: print ("Both are not same") ##variable to store sumOfFloat=0.0 sumOfFloatreverse- 0.0 number-l ##calculating the number by adding 0.1 while (number< -1000000) sumOfFloat-sumOf Float+number every time till number-number+0.1 print ("Double floating point from l to 1000000 number 1000000 calculating the number by substracting the 0.5 every time and checking while (number> 1 ) sumofFloatreverse -sumOfFloatreverse+number ', sumOfFloat) number-number-0.1 print ("Double floating point from 1000000 to l",sumOfFloatreverse) #check for equality if (sumOfFloat-= sumOfFloatreverse) print ("Both are same ") else: print ("Both are not same")