Question

The following program source code is incomplete 1 #include <stdio.h> 2 3 // TODO: 1) Add the typedef here: 5// TODO: 2) Modify the parameter of repeat to add irn the function pointer for the function to be called repeatedly: 8 void repeat (int times) for (int k 0; k < times; ++k) 12 // TODO: 3) Add the call to the function pointer here: 14 15 17 void test (void) 18 printf("Test!\n"); 19 20 21 22 int main (void) 23 24 // TODO: 4) Modify this call to pass in test: repeat (10) 25 26 27 // TODO: 6) Add another call to your void function: 28 29 return 0; 30 32 // TODO: 5) Add your own void function, and prototype: To complete the program, add a typedef for a function pointer where the function return:s nothing, and takes in no parameters. Modify the repeat function to add a second parameter of the function pointer typedef, which is the address of the function to be repeatedly called times number of times upon calling repeat. Next, modify the call to repeat in the main function to pass in the address of the test function Finally, add your own void function that can be used with the repeat function. In the mairn function, add a call to repeat using your new function as an argument. Ensure the whitespace of your source code is well formatted

Please in C Language

Thank you!

Answer 1

#include<stdio.h>
typedef void (*fun_ptr)(void);
void temp(void);

void repeat(int times ,fun_ptr func)
{
for(int k=0;k<times;++k)
{
(*func)();
}
}
void test(void)
{
printf("Test!\n");
}
int main() {
repeat(10,&test);

repeat(10,&temp);

return 0;
}
void temp(void)
{
printf("My function\n");
}

The output is

Test! Test! Test! Test! Test! Test! Test! Test! Test! Test! My function My function My function My function My function My function My function My function My function My function

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