Question

The 24-kg roll of paper has a radius of gyration ka = 90 mm about an axis passing through point A. It is pin supported at both ends by two brackets AB. The roll rests against a wall for which the coefficient of kinetic friction is like = 0.2 and a vertical force F = 29 N is applied to the end of the paper. (Figure 1) Part A Determine the angular acceleration of the roll as the paper unrolls Express your answer using three significant figures. Enter positive value if the angular acceleration is clockwise and negative value if the angular acceleration is counterclockwise. AEO vec ? a = 2.97 rad/s2 Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Provide Feedback Figure < 1 of 1 > 300 mm 125 mm

Answer 1

Draw the the free body diagram. TAG tand = 300 125 o We o 67.38 मा. ing Is fm = Ne - Tag cos 67.38° = 0 TAB Cos 67.38 ]

+1 Ef - «9 = 0 Tarsin 67.238 o ana 24 x 9.81 from equal 18 Ne fsin 67.38°) 20:2N 264.44 Nel tan 67.38° - 0.2) = 264.44 Ne 120.2N 046738 et EM In a -0.2 NX 0.125 + EX00125 20x[0:09j25 (o'dx12012 + 910.185 = 0.16ad a = 4.96 Xo'lds 0:16 2 3.83 rad/52€ final Answer