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Here are summary statistics for randomly selected weights of newborn girls: n= 176, x-28.5 hg, s = 7.2 hg. Construct a confid

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Answer #1

Here n is sufficient large so we will use z distribution to find CI

z value for 90% CI is 1.645 as P(-1.645<z<1.645)=0.90

Hence Margin of Error is E=…sn = 1.645 * v.176 7.2 = 1.645 *-= 0.9

Hence CI is T± E 28.5 0.9 (27.6. 28.9)

So answer is 27.6ha < μ< 28.9hq

Yes it is different from 26.7 hg <p < 29.5 hg with only 16 sample values, x = 28.1 hg, and s = 3.1 hg

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