Question

11. By solving an appropriate linear system, find the loop currents in the following circuit. 201 10v 100+ 3 T 14 В

Answer 1

20V 0 1+ 22 toop-1 ICOP-I 100P-II 100p-IEL 10v 11 44 45 }282 +140 452 22 B 3v 12c For loop-I by applying KVL we get 4(1,-12) +21, -10 = 0 => 61, - 412 = 10 - ☺ for 2009. It by applying Kve we get 20+212 + 2(12 – 13) + 12 -3 + 4(12-1,) = 0

=> 912 – 213 - 41, +1720 = -(41, +293 - 91, - 7) = 0 -) 41,-952+2 13 = 17 —-_>©

for loop-fff by applying Kv2 equation we get -14 +463 +2 (13 - 12) = 0 => -212 +613 = 14 ->

☺ we get From equation o 61, = 10 +412 f = 10 + 4 12 Now putting the value of I, in equ 4(104952) -9 12 +2 E3 = 17 => 3 + 12 -91, +213 = 17 → Iz ( 8=27) + 25z = 17 - 23 -7 -2 12 +213 = şi-20 => -1984 +683 = 32 - © Subtracting ear from ean we get -1912 +212 = 31-14 = - 17I2 = 17 = I2 = - 1 Amp. putting the value of Iz in ean ☺ we get 61, +4=10 611 = 6 . I, = 1 Amp.

Iz in Ean we get putting the value of 2 + 623 = 14 => 6I3 =12 > Iz =2 Amp. o. The loop cuprents will be I = 1 Amp, 2. I2 =-1 Amp. Iz = 2 Amp.