Question

Assignment Score: 63% Resources Hint Check Answer uestion 29 of 30 > Calculate the volume, in liters, occupied by 1.89 mol of oxygen gas at STP. V =

Answer 1

Answer :- V = 42.3 L

solution :-

since we know that

from ideal gas equation,

PV = nRT

so ,

V = nRT / P ................. eqn 1

it is given that

n= 1.89 moles

At STP

P = 1 atm

T= 273 K

R = 0.082057 Latm / mol K

So from equation 1

V = 1.89 *0.082057*273 / 1

V = 42.3 L (answer must have three significant figure)

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