I am little confused on this problem..g(t) = 3π sin(8πt + 1.3)cos(4πt − 0.8) e^sin(12πt)
MATHLAB help
The energy in a signal during the time interval [t1 , t2] is given by the following formula
The power of the signal in the time interval [t1,t2] is given by following formula
In the question , it is given that
We are going to find the above integrals using MATLAB . In MATLAB integration is nothing but summation multiplied by step size h. The code is given below followed by output. In the code we defined as array from 0.25 to 0.75 with step size of 0.0001. Then g is calculated at each value of t. Important thing is , In element by element multiplication we should use ' .* ' instead of simple *.
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t = 0.25:0.0001:0.75;
g=3*pi.*sin(8*pi*t+1.3).*cos(4*pi*t-0.8).*exp(sin(12*pi*t));
E=0.0001*sum(abs(g.^2))
P=0.0001*sum(abs(g.^2))/0.5
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The output is
>> Energy_of_signal
E =
27.3815
P =
54.7630
>>
I am little confused on this problem..g(t) = 3π sin(8πt + 1.3)cos(4πt − 0.8) e^sin(12πt) MATHLAB...
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