![take B 2.5 T, v 4 m/s, 30 cm, and 2. In the generator rod increase in magnetic flux in one 4 current 2.0 A, clockwise. Find (a) the rod-the external R 2 second, (b) the emf, (c) the magnetic back-force on the at which electrical force needed to keep it moving. Calculate the rate force does energy is produced by the emf, and which the external 1.50]. work, showing equality. (e) Find the resistance of the circuit 3. In #2, now assume that a second, motor-rod is moving at 3.2 m/s, with all given data the same. Find (a) the magnetic force on the motor-rod and the back-emf on it. (c) Find the net emf, and use this to find (d) the resistance r in this circuit. (e) Find the rate of production of mechanical energy and of heat, and check consistency with a preceding result. What determines which rod is the generator and which the motor? What would happen if the two rods moved at the same speed?](http://img.homeworklib.com/questions/2e202c00-1938-11ec-83d8-9fb972457bc5.png?x-oss-process=image/resize,w_560)
Homework Answers
magnetic flux = B*A = B*l*dx
rate of change in flux = B*i*dx/dt = B*l*v = 2.5*0.3*4 = 3
V
------------
(b)
emf = rate of change in flux = 3 V
-------------
(c)
F = I*l*B = 2*0.3*2.5 = 1.5 N
-------------------
(d)
rate of electrical energy = e*I = 3*2 = 6 W
(ii)
Work = F*v = 1.5*4 = 6 W
==============
(e)
rate of energy = i^2*R
R = 6/2^2 = 1.5 ohms
============================================
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