We can now use the Lens Equation to find the Focal Length. What would be the...
Each of your eyes has a lens in it. This lens can change its shape and hence its focal length. By changing the focal length you are able to focus on an object based on how far away it is from you. For this problem you will determine the minimum focal length of your eye. A. Hold an object out in front of you at arm's length. Close one eye and bring the object towards your eye and determine how...
1. Using the thin lens equation (1/f=(1/s)+(1/s')), prove that the focal length of a lens is equal to the image distance when there is parallel incident light 2. There is a specific case where for a single converging lens the object distance equals the image distance. Find the relation between the focal length and the object distance in this case.
number 3 please
2. Calculate the image distance from the equation-+-=- PS: for a concave mirror, the focal length is taken to be positive (); for a convex mirror, the focal length is taken to be negative ). The object distance do is taken to be positive in either case. The sign convention is as Tollows: If di is positive, the image is real, and if di is negative, the image is virtual. 3. How might you determine the focal...
A microscope has an objective lens with a focal length of 19.5 mm and an eyepiece with a focal length of 6.2 mm. With the length of the barrel set an 33.0 cm, the diameter of a red blood cell’s image subtends an angle of 1.2 milli-radians with the eye. The final image distance is 29.0 cm from the eyepiece. (a) What is the length of the image of the of the cell produced by the eyepiece? (b) Using the...
2. A camera has a single converging lens with a fixed focal length f. (a) How far should the lens be from the film in order to focus an object that is infinitely far away (namely the incoming light rays are parallel with the principal axis of the system) (b) How far should the lens be from the film to focus an object at a distance of 2f in front of the lens? (c) What is the magnification of the...
A concave lens has a focal length of -36 cm. Find the image distance and magnification that results when an object is placed 19 cm in front of the lens. (Use the proper sign convention for both quantities.) When an object is located 61 cm to the left of a lens, the image is formed 25 cm to the right of the lens. What is the focal length of the lens? An object with a height of 2.22 cm is...
The next few questions give you the chance to use the Lens Equation that relates the object distance, Xo, image distance, Xi, and focal length of a lens, F, by: This equation comes from considering the ratio of side lengths of various triangles that are formed in ray diagrams of the type that you have been doing for the last week. There are a few rules you need to follow to play the game and to understand the results. Here...
A real object is 13.6 cm to the left of a thin, diverging lens having a focal length of magnitude 24.5 cm. (a) is the sign of the focal length negative or positive? negative positive (b) Find the image distance. (c) Find the magnification. (d) State whether the image is real or virtual. real virtual (e) State whether the image is upright or inverted. upright inverted
A negative or diverging thin lens has a focal length of 10 cm. a) An object is placed 30 cm from the lens. Find the image distance and explain if the image is real or virtual. b) Explain if the image is upright or upside down and if it is smaller or larger than the object.