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41) A negative or diverging thin lens has a focal length of 10 Show Calculation: a) An object is placed 30 cm from the lens. Find image distance and explain ifthe image is real or virtual (4 pts) b) Explain if the image is upright or upside down and if it is smaller or larger than the object. (2 pts)

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Answer #1

here,

the focal length of the lens , f = - 10 cm

a)

the object distance , do = 30 cm

let the image distance be di

using the lens formula

1/f = 1/di + 1/do

- 1/10 = 1/30 + 1/di

di = - 7.5 cm

the image distance is - 7.5 cm

as di is -ve , the image is virtual

b)

the image is upright

magnification , m = -di/do

m = - 7.5/30 = 0.25

so the image is smaller than the object

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