Question

The focal length of a diverging lens is negative. If f = −23 cm for a particular diverging lens, where will the image be formed of an object located 32 cm to the left of the lens on the optical axis?

______cm to the left of the lens?

What is the magnification of the image?

b.

A small object is placed to the left of a convex lens and on its optical axis. The object is 29 cm from the lens, which has a focal length of 12 cm. Determine the location of the image formed by the lens. (Enter your answer in cm from the lens.)

cm from the lens

Describe the image. (Select all that apply.)

real

virtual

upright

inverted

enlarged

reduced

on the left side of the lens

on the right side of the lens

Answer 1

using lens formula

1/f = 1/v - 1/u

-1/23 = 1/v + 1/32

v = 13.382 cm, to the left of lens

b)

magnification

m = v/u = 13.382 / 32 = 0.4182

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2.

again

1/12 = 1/v +1/29

v = 20.47 cm

image properties

virtual, upright, enlarged and to the left of the lens

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