Consequences of the uncertainty principle - electron
What would be the corresponding kinetic energy in MeV of an electron localised to within such a region as in the following question for the neutron? Take the rest mass of the electron to be 0.511 MeV. Give your answer to 3 significant figures.
Consequences of the uncertainty principle - electron What would be the corresponding kinetic energy in MeV...
Suppose that an electron is traveling at 0.7 c. What is the Rest Energy of the electron? Use 9.11 x 10-31 kg for the mass of the electron, use c = 2.9979 x 108 m/s, calculate the Rest Energy in units of Joules, convert the units to eV, and then convert the units to MeV. Give your answer in MeV. What is the mass of the electron in units of MeV/c2? Use your answer for the mass of the electron...
An electron-positron pair is produced by a 2.85 MeV photon. What is the kinetic energy of the positron if the kinetic energy of the electron is 1.219 MeV? Use the following Joules-to-electron-Volts conversion 1eV = 1.602 × 10-19 J. The rest mass of an electron is 9.11 × 10-31 kg Please answer in MeV
An electron-positron pair is produced by a 2.30 MeV photon. What is the kinetic energy of the positron if the kinetic energy of the electron is 0.958 MeV? Use the following Joules-to-electron-Volts conversion 1eV = 1.602 × 10-19 J. The rest mass of an electron is 9.11 × 10-31 kg
Using the Heisenbery's uncertainty principle Deltap middot DeltaX Greaterthanorequalto h Determine how much kinetic energy is required, on average, to localize a 1g mass with accuracy of 10^-5 cm? Calculate how much kinetic energy is required to localize a proton within one atomic radius(take 10^-10 m) Calculate how much kinetic energy is required to localize on electron within the same distance?
*PET SCAN* A typical kinetic energy of the positron emitted from F-18 is 0.2 MeV. What is a typical speed of positron in unit of c (=speed of light)? (Hint: The rest mass of positron is 0.511 MeV/c2 . The total energy = kinetic energy + rest mass). c) The half-life of F-18 is roughly two hours. How long does it take to reduce the radioactivity down to 12.5% (= 1/8) level (so that a patient becomes safe to meet...
3. A photon creates a electron-positron pair. The kinetic energy of the electron is 2.20 times that one of the positron. What is the kinetic energy of the electron if the energy of the photon is 2.80 times the rest mass energy of the electron? (The rest mass of a electron is 9.11 x10-31 kg.) O 0.128 MeV O 0.819 MeV O 0.281 MeV O 0.409 MeV O 0.186 MeV
h where ħ=__=1.054 x 10-34 Js 27 Uncertainty principle Question) Uncertainty in position of an electron is 1 nm. Estimate the minimum uncertainty in momentum and the corresponding kinetic energy.
Part B The uncertainty ?p sets a lower bound on the average momentum of a particle in the nucleus. If a particle's average momentum were to fall below that point, then the uncertainty principle would be violated. Since the uncertainty principle is a fundamental law of physics, this cannot happen. Using ?p=2.1×10?20 kilogram-meters per second as the minimum momentum of a particle in the nucleus, find the minimum kinetic energy Kmin of the particle. Use m=1.7×10?27 kilograms as the mass...
An proton-antiproton pair is produced by a 2.05×1032.05×103 MeV photon. What is the kinetic energy of the antiproton if the kinetic energy of the proton is 86.90 MeV? Use the following Joules-to-electron-Volts conversion 1eV = 1.602 × 10-19 J. The rest mass of a proton is 1.67×10−271.67×10−27 kg. _______________ MeV
10. An proton-antiproton pair is produced by a 2.10×1032.10×103 MeV photon. What is the kinetic energy of the antiproton if the kinetic energy of the proton is 55.95 MeV? Use the following Joules-to-electron-Volts conversion 1eV = 1.602 × 10-19 J. The rest mass of a proton is 1.67×10−271.67×10−27 kg. MeV