Question

Write a C++ program that defines a structure called StudentInfo for records consisting of a student’s ID, age, final grade for math, final grade for reading, and final grade for music. Define an array of such records to hold up to eight students’ records that the user input students’ information from the keyboard. Then compute and print out the average of their math grades and average of reading, and each student’s average grade of math, reading and music

.

Answer 1

C++ Program:

/* C Program that reads student data from user and stores in struct Array and displays their averages */

#include <iostream>

using namespace std;

//Structure definition
struct StudentInfo
{
//Student data
int id;
int age;
double mathGrade;
double readingGrade;
double musicGrade;
};

//Main function
int main()
{
int i;

double sumMathGrade = 0, sumReadingGrade = 0, sumMusicGrade = 0, sumGrade = 0;

double avgMathGrade, avgReadingGrade, avgMusicGrade, avgGrade;

//Array of 8 students
struct StudentInfo students[8];

//Reading data from user
cout << "\n Input Student data as id [Space] age [Space] mathGrade [Space] readingGrade [Space] musicGrade [Space]: \n\n ";

//Looping over each student data
for(i=0; i<8; i++)
{
cout << "\n Student " << (i+1) << " data: ";

//Reading student data
cin >> students[i].id >> students[i].age >> students[i].mathGrade >> students[i].readingGrade >> students[i].musicGrade;
}

//Looping over each student data
for(i=0; i<8; i++)
{
//Calculating sum of grades
sumGrade = students[i].mathGrade + students[i].readingGrade + students[i].musicGrade;

//Calculating average of grades
avgGrade = sumGrade / (double)3;

//Printing individual average grade
cout << "\n Student Id: " << students[i].id << " \t Average grade of math, reading and music : " << avgGrade ;

//Accumulating each grade
sumMathGrade += students[i].mathGrade;
sumReadingGrade += students[i].readingGrade;
sumMusicGrade += students[i].musicGrade;
}

//Finding average of each grade
avgMathGrade = sumMathGrade / (double)8;
avgReadingGrade = sumReadingGrade / (double)8;
avgMusicGrade = sumMusicGrade / (double)8;

//Printing average of each grades
cout << "\n\n Average of math Grades: " << avgMathGrade;
cout << "\n\n Average of reading Grades: " << avgReadingGrade;
cout << "\n\n Average of music Grades: " << avgMusicGrade << " \n";

return 0;
}

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Sample Output:

CATCStudentsInformation bin Debug StudentsInformation.exe Input Student data as id [Space] age [Space] mathGrade [Space] readingGrade [Space] musicGrade [Space]: Student 1 data: 111 23 56.8 65.4 45.5 Student 2 data: 222 25 45.5 65.22 54.5 Student 3 data: 333 21 65.4 52.4 58.5 Student 4 data: 444 28 48.5 65.5 48.5 Student 5 data: 555 24 79.5 55.5 45.6 Student 6 data: 666 22 64.7 68.9 78.5 Student 7 data: 777 24 49.5 65.5 66.8 Student 8 data: 888 23 53.2 54.5 59.8 Student Id: 111 Student Id: 222 Student Id: 333 Student Id: 444 Student Id: 555 Student Id: 666 Student Id: 777 Student Id: 888 Average grade of math, reading and music 55.9 Average grade of math, reading and music 55.0733 Average grade of math, reading and music 58. 7667 Average grade of math, reading and music 54.1667 Average grade of math, reading and music 60.2 Average grade of math, reading and music 70.7 Average grade of math, reading and music 60. 6 Average grade of math, reading and music 55.8333 Average of math Grades: 57.8875 Average of reading Grades: 61.615 Average of music Grades: 57.2125 Process returned 0 (0xO) execution time 106. 913 s Press any key to continue.