Question

Chapter 34, Problem 85 GO Your answer is partially correct. Try again. In the figure below, stick figure 0 (the object) stands on the common central axis of two thin, symmetric lenses, which are mounted in the boxed regions. Lens 1 (mounted in box 1) is a converging lens, 0 is at object distance p1 = 3.00 cm, and the distance between the lens and its focal point is 9.00 cm. Lens 2 (box 2) is a diverging lens at distance d = 17.0 cm, and the distance between the lens and its focal point is 9.00 cm. What is the overall magnification of the system? Number 1.10232 Units This answer has no units

Answer 1

For the first lens, to determine the image distance, the lens equation can be used:

1/9 =1/3 -1/di

or, di = -4.5 cm ( i. e 4.5 cm behind the lens)

m1 = -di/do = 4.5/3 = 1.5

For the second lens,

-1/9 = 1/(9-4.5) + 1/di

or, di = -3 cm

m2 = -di/do = 3/4.5 = 0.67

Overall m = m1*m2 = 0.67*1.5 = 1