Each plate of a parallel-plate capacitor is a square of side 0.0313 m and the plates...
Each plate of a parallel-plate capacitor is a square of side 0.0313 m and the plates are separated by 0.423
Homework Answers
Area
A=S2=0.03132=9.8*10-4 m2
Capacitance
C=eoA/d=(8.85*10-12)(9.8*10-4)/(0.423*10-3)
C=2.05*10-11 F
Energy stored in capacitor
E=(1/2)CV2
=>V=sqrt[2*E/C]=sqrt[2*8.83*10-9/2.05*10-11]
V=29.35 volts
Electric field
E=V/d=29.35/(0.423*10-3)
E=6.94*104 N/C
Since C=e0A/d=8.85x10-12 x 0.0313x0.0313/0.000423=20.5x10-12F
also
U=1/2CV2
V=sqrt(2U/C)=sqrt( 2 x 8.83x10-9/20.5x10-12)=29.35V
E=V/d=29.35/0.000423=69387N/C
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