Question

The loop in the figure has an induced current as shown. The loop has a resistance of 0.28 Ω .

What is the rate of change of the field, ΔB/ΔtΔB/Δt?- 150 mA x x 8.0 cm x x x x x x x xxx x x x x x x x x 8.0 cm

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Answer #1

Induced emf = v= JR = 6015 x 0.28 ) volt Induced emt v - IR 15% O. Now vs da s dB dt 0.15 0.28 1 ADE (0.0872 = 6.5625 TIS!

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