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3. The loop (h=7.6 cm square) in the figure to the right has an induced current of 250 mA as shown. The loop has a resistance
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given induced current iz 250 mA i= 250 8103A R = 1.500 using ohns low Lw- di , VE IR = (250x153)x1.5 V = 0.375 Emf induced =- (6) According to Faradays Law Emf induced = 1 - do = - (Rate of charge of flux) d = BA Here A = area is constant a hw = (7

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