Solution) R = 0.500 ohm
r = 8.10 cm = 8.10×10^(-2) m
I = 3.20 mA = 3.20×10^(-3) A
(a) it indicates increasing magnetic field
(b) dB/dt = ?
I = E/R
E = - d(phi)/dt
phi = B.A = B.(pi)(r^2)
E = (pi)(r^2)(dB/dt)
I = ((pi)(r^2)(dB/dt))/(R)
(dB/dt) = ((I)(R))/((pi)(r^2))
dB/dt = (3.20×10^(-3)×0.500)/((pi)(8.10×10^(-2))^2)
dB/dt = 0.0776 T/s
dB/dt = 77.6 mT/s
A circular loop of wire of resistance - 0.500 and radius 8.10 cm is in a...
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