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i am confuses how to calculate Ecell where non-standard
condition for this question
For the following...
For the following questions: a)Calculate ??????for the spontaneous reaction b)Write the overall cell equation c)Write the...
For the following questions: a)Calculate ??????for the spontaneous reaction b)Write the overall cell equation c)Write the cell notation for the cell d)Calculate ??? e)Calculate ?????where non-standard conditions are stated 1)cell is made from the ??3+,(??,0.10?)|??and the ???4-(??,0.25?)|??2+,(??,1.50?)half cells, where pH is 1.67 at 298 K(no need to calculate ???for this Q) 2)A cell is made from the ??|??+,(??,0.010?)and the ???4-(??,2.0?)|???2half cells, where pH is 0 at 298 K(no need to calculate ???for this Q)
QUESTION 27 Calculate Ecell under non-standard conditions for the following electrochemical cell: Pt(s)| FeCl2 (aq, 0.150...
QUESTION 27 Calculate Ecell under non-standard conditions for the following electrochemical cell: Pt(s)| FeCl2 (aq, 0.150 M), FeCl3 (aq, 0.050 M) || Cl2 (9, 1 atm), NaCl (aq, 0.075 M) | Pt (s) -1.60 V 0.72 v 0.69 V -1.79 V 0.62 V none of these
the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) fone 2...
the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) fone 2 pts) a. Use the standard half-cell potentials listed below to calculate the standard cell potential (Eºcell) for 3 Sn(s) + 2 Fe* (aq) - 3 Sn2+ (aq) + 2 Fe(s) Sn 2(aq) + 2 e -Sn (s) E = -0.14 V Fe3+ (aq) + 3 e Fe(s) E° = -0.036 V A) -0.176 V B)-0.104 V C) +0.104 V D) +0.176 V b. Write...
Voltaic cells chemistry please help with A-C, H and I. 3. A voltaic cell is built...
Voltaic cells chemistry
please help with A-C, H and I.
3. A voltaic cell is built from two half-cells using the reduction reactions given below: Sn 2(aq) → Sn(s); Eredn = -0.14 V Cr20;2(aq) → Cr+ (aq) Eredin = 1.33 V a) Write the balanced cathode half reaction in acidic medium: (show work step by step and box your answer) b) Write the balanced anode half reaction and box your answer: c) Write the balanced overall cell reaction and box...
Calculate the Ecell value at 298 K for the cell based on the reaction: Cu(s) +...
Calculate the Ecell value at 298 K for the cell based on the reaction: Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s) where [Ag+] = 0.00350 M and [Cu2+] = 7.00x10-4 M. The standard reduction potentials are shown below: Ag+(aq) +e → Ag(s) E° = 0.7996 V Cu2+ (aq) + 2e -→ Cu(s) E° = 0.3419 V 2nd attempt Ecell = V
2. Calculate the standard cell emf (cell potential) for electrochemical cells having the following overall cell...
2. Calculate the standard cell emf (cell potential) for electrochemical cells having the following overall cell reactions and predict if they are spontaneous: a) Sn(s) + Pb2+ (aq) → Sn?" (aq) + Pb(s) Eºcell = Volts. Spontaneous? b) 2002 (aq) + Zn?"(aq) → 2Co3+ (aq) + Zn(s) Eºcell__volts; Spontaneous? c) Cl2(g) + 2Br (aq) + 2Cl(aq) + Br2(1); E° = volts; Spontaneous?
Use the standard reduction potential values from your chemistry data sheet to answer this question. The...
Use the standard reduction potential values from your chemistry data sheet to answer this question. The following electrochemical cell has a potential of Ecell = 0.322 V at 298 K: Sn (s) | Sn2+ (aq) (0.025 M) || M2+ (aq) (0.010 M), M+ (aq) (0.025 M) | Pt(s) Where M2+and M+ are ions of an unknown metal. First, determine the standard potential of the anode (EA°) -0.138 V +0.138 V 0.00 V None of the above What is the value...
Given the measured cell potential, Ecell, is-0.3583 V at 25 °C in the following cell, calculate...
Given the measured cell potential, Ecell, is-0.3583 V at 25 °C in the following cell, calculate the Ht concentration Pt (s)|H2lg, 0.795 atm)lH (aq, ? M)l|Cd2 (aq, 1.00 M)|Cd (s) The balanced reduction half-reactions for the cell, and their respective standard reduction potential values, E°, are as follows. 2H+(aq) + 2e- H2(g) E0.00 V E-0.403 V ? 2 + Number H0.21
Calculate Ecell for the following electrochemical cell at 25 degreeC Pt(s) | H2(g, 1.00 atm) |...
Calculate Ecell for the following electrochemical cell at 25 degreeC Pt(s) | H2(g, 1.00 atm) | H+ (aq, 1.00 M) || Pb2+(aq, 0.150 M) | Pb(s) given the following standard reduction potentials. Pb2+(aq) + 2 e– --> Pb(s) Edegree = –0.126 V 2 H+ (aq) + 2 e– --> H2(g) Edegree = 0.000 V (Please show the steps)
Name SHOW ALL WORK. NO CREDIT UNLESS ALL WORK IS SHOWN. ROUNDING/SIG FIG ERRORS WILL BE...
Name SHOW ALL WORK. NO CREDIT UNLESS ALL WORK IS SHOWN. ROUNDING/SIG FIG ERRORS WILL BE PENALIZED. 1. Parts a-j of this question refer to the following cell at 298 K. Complete the diagram of the following voltaic cell: Silver and iron electrodes, aqueous Silver nitrate, aqueous iron (UI) nitrate, potassium nitrate salt bridge. Fe3+ (aq) + 3e → Fe (s) Ag (aq) + e - Ag(s) E° -0.040 V Eº= 0.795 V a. Identify the electrodes as Anode or...
QUESTION 27 Calculate Ecell under non-standard conditions for the following electrochemical cell: Pt(s)| FeCl2 (aq, 0.150 M), FeCl3 (aq, 0.050 M) || Cl2 (9, 1 atm), NaCl (aq, 0.075 M) | Pt (s) -1.60 V 0.72 v 0.69 V -1.79 V 0.62 V none of these
the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) fone 2 pts) a. Use the standard half-cell potentials listed below to calculate the standard cell potential (Eºcell) for 3 Sn(s) + 2 Fe* (aq) - 3 Sn2+ (aq) + 2 Fe(s) Sn 2(aq) + 2 e -Sn (s) E = -0.14 V Fe3+ (aq) + 3 e Fe(s) E° = -0.036 V A) -0.176 V B)-0.104 V C) +0.104 V D) +0.176 V b. Write...
Voltaic cells chemistry
please help with A-C, H and I.
3. A voltaic cell is built from two half-cells using the reduction reactions given below: Sn 2(aq) → Sn(s); Eredn = -0.14 V Cr20;2(aq) → Cr+ (aq) Eredin = 1.33 V a) Write the balanced cathode half reaction in acidic medium: (show work step by step and box your answer) b) Write the balanced anode half reaction and box your answer: c) Write the balanced overall cell reaction and box...
Calculate the Ecell value at 298 K for the cell based on the reaction: Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s) where [Ag+] = 0.00350 M and [Cu2+] = 7.00x10-4 M. The standard reduction potentials are shown below: Ag+(aq) +e → Ag(s) E° = 0.7996 V Cu2+ (aq) + 2e -→ Cu(s) E° = 0.3419 V 2nd attempt Ecell = V
2. Calculate the standard cell emf (cell potential) for electrochemical cells having the following overall cell reactions and predict if they are spontaneous: a) Sn(s) + Pb2+ (aq) → Sn?" (aq) + Pb(s) Eºcell = Volts. Spontaneous? b) 2002 (aq) + Zn?"(aq) → 2Co3+ (aq) + Zn(s) Eºcell__volts; Spontaneous? c) Cl2(g) + 2Br (aq) + 2Cl(aq) + Br2(1); E° = volts; Spontaneous?
Given the measured cell potential, Ecell, is-0.3583 V at 25 °C in the following cell, calculate the Ht concentration Pt (s)|H2lg, 0.795 atm)lH (aq, ? M)l|Cd2 (aq, 1.00 M)|Cd (s) The balanced reduction half-reactions for the cell, and their respective standard reduction potential values, E°, are as follows. 2H+(aq) + 2e- H2(g) E0.00 V E-0.403 V ? 2 + Number H0.21
Name SHOW ALL WORK. NO CREDIT UNLESS ALL WORK IS SHOWN. ROUNDING/SIG FIG ERRORS WILL BE PENALIZED. 1. Parts a-j of this question refer to the following cell at 298 K. Complete the diagram of the following voltaic cell: Silver and iron electrodes, aqueous Silver nitrate, aqueous iron (UI) nitrate, potassium nitrate salt bridge. Fe3+ (aq) + 3e → Fe (s) Ag (aq) + e - Ag(s) E° -0.040 V Eº= 0.795 V a. Identify the electrodes as Anode or...
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