Question

You want to cool 250 gr of Cola (mostly water) initially at 528 Ra. by adding ice initially at 428 Ra. How much ice should you add so that the final temperature will be 492 Ra with all the ice melted? (Conservation of Heat)

Answer 1

Relation betweeen centigrade and Rankine scale is Ra - 32-459.67 7(C)- Initi al temperature of cola is, 528-32-459.67 7(°C)- -20, 18"C Initi al temperature of ice is 428- 32-459.67 (°C)- -35.37"C Equilibrium temperature of the mixture is, 492-32-459.67 T, c)- eg -0.18 C Let x grms of ice in the system ,from calorim etry principle (Heat lost (Heat gain), (250g)(1.0cal/g)( 20. 18"C-0)-x(0.5 cal/g )(0-(-35. 37°C))-x(80cal/gm) 5045 cal-r(0.5cal/g )( 35.37.C)-(80 cal/gm)) Solve for x-5 1.6 gm Amount of ice 1 s added is 5 1 . 6gm ~ 52 gm