Question

A closed tank at an elevation of 21 = 15 m is completely filled with 0.005 kg of saturated liquid H2O at Ti = 200 °C and is attached to a paddle wheel. Take the reference state to be To = 25°C and po = 101.3 kPa. Calculate the exergy transfer due to the process and the amount of exergy destroyed in kJ, if the only occurring process is: referente state to be Tieten die and (a) 1 kJ of potential energy is gained due to change in height. Note: Approximate compressed liquid properties with saturated liquid properties

Answer 1

. When with atm the regatem Sretraction of then , come To=25°c Po= 101.3K 0.005 kg Z-15m 2000 a "O to surrounding Now co AE = (Ug-Vo) - To (Si-so) - Watma Since there is no change in freot val Watrn = 0 Sy s = Op GTITO) -T, CE -6.7+ 32;+ PE 20mm 24.18 (200-25)-}298 X 4:1 & 9.21X25X153 + PE 3931,5 -429894+43 6 (413) } = 732-5-575.48 +0.147+ PE = 156.167 kJ + PE = m ( 156. 1673 + 1 = 0.005 (156.167) + 3 = 1.RO KI Now point of energy destroyed (S.) of water = 0.005 X 4.72 ln (473) = 9.65 x10 3 KIK 1:38 (200-25) de atm a 298 = 0.0122 Kolk (OS) gen = (Sp.So) Hot Malm

(AS) gen= Energy 9.65x10 3 + 0.0122 0.0219 KOIR destroyed? It means hass of Anailable Energy. - Increment in unauciloble energy, Geng Stodola Thearem. I = To (ogen from = 298 X 600219) = 6.53 kJ