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A sample of pure aluminum has a mass of 15.2 g Calculate the number of moles in the sample and aluminum atoms in the sample (
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Answer #1

Shift mass of a I mole of aluminium Number of males n= 15.2 m=26.998 - 0.563 male 26.90 (6 I male = 6.023x102 adoms so number(6) V = 175 101325 x x Px0. 26X = P x 0.26X Pa. - = Pf = 437883.5 9 283.15 318.15 New final volume V = 1.03x0.26 V, Newfinal.

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