Solve: (0≤x<2π) a. tan 2x = cot 2x b. 2cos^2 x+cosx - 1=0
Solve: (0≤x<2π)
a. tan 2x = cot 2x
b. 2cos^2 x+cosx - 1=0
Homework Answers
Solve the equation for the interval [0, 2π). cos^2x + 2 cos x + 1 =...
Solve the equation for the interval [0, 2π). cos^2x + 2 cos x + 1 = 0 2 sin^2x = sin x cos x = sin x sec^2x - 2 = tan^2x
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(1 point) If tan x - -1/3, cosx > 0,, then sin 2x- cos 2x - tan 2x - (1 point) Find cos 29 if sin- 13 85
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Solve the equation for the interval [0, 2π). tan x + sec x = 1 csc^5x - 4 csc x = 0 sin^2x - cos^2x = 0 sin^2x + sin x = 0
Verify the identity: tan^2x/1+secx = 1-cosx/cosx
Verify the identity: tan^2x/1+secx = 1-cosx/cosx
2. Solve 2 sec @ + tan 0 = 2 cose, 050<21. 3. Solve cos 2x...
2. Solve 2 sec @ + tan 0 = 2 cose, 050<21. 3. Solve cos 2x + 3 sin r-2=0, 0 <x<360°.
need help with #8, 10 and 11 please! 8. cos x tan x-3cos x=0 Use Identities...
need help with #8, 10 and 11 please!
8. cos x tan x-3cos x=0 Use Identities to Solve Trigonometric Equations Solve on the interval [0,2x). (compare to #7) 9. 2 sin'x-5 cos x+S=0 211-cos? (x) - Scos(x)+s=0 - 2 cos? (x) - 5 cos(x) + 750 2 cos (X)(-cosx+1)+7 (-cosx+1)=0 COSXFO 2 cosx+7=0 X=0 10. sin 2x = cos X 11. sin x = COS X
verify the following 1) tan x+cot y= sin(x+y)/cos x sin y 2) tan 5x + cot 5x = 2 csc 10x
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1. For all x, the function f(x) = tan-',+ cot-1, has derivative f'(z)-12-17 0 1 +22...
1. For all x, the function f(x) = tan-',+ cot-1, has derivative f'(z)-12-17 0 1 +22 So f(x) must be a constant. a) What is that constant ? b) Explain by using a triangle c) What is limz+ */2-tan cot
Use trigonometric identities to solve the equation 2sin(2θ)-2cos(θ)=0 exactly for 0≤θ≤2π. A.) What is 2sin(2θ) in...
Use trigonometric identities to solve the equation
2sin(2θ)-2cos(θ)=0 exactly for 0≤θ≤2π.
A.) What is 2sin(2θ) in terms of sin(θ)and cos(θ)?
B.) After making the substitution from part 1, what is the
common factor for the left side of the expression
2sin(2θ)-2cos(θ)=0 ?
C.) Choose the correctly factored expression from below.
a.)
b.)
c.)
d.)
We were unable to transcribe this imageAsin(e) cos(O) = 2cos(e) We were unable to transcribe this imageWe were unable to transcribe this image
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Solve the separable initial value problem. tan(sin(x^(2) 1. y' = 2x cos(x2)(1 + y2), y(0) = 5 → y= 2. v' = 8e4x(1 + y2), y(0) = 2 + y=
(1 point) If tan x - -1/3, cosx > 0,, then sin 2x- cos 2x - tan 2x - (1 point) Find cos 29 if sin- 13 85
2. Solve 2 sec @ + tan 0 = 2 cose, 050<21. 3. Solve cos 2x + 3 sin r-2=0, 0 <x<360°.
need help with #8, 10 and 11 please!
8. cos x tan x-3cos x=0 Use Identities to Solve Trigonometric Equations Solve on the interval [0,2x). (compare to #7) 9. 2 sin'x-5 cos x+S=0 211-cos? (x) - Scos(x)+s=0 - 2 cos? (x) - 5 cos(x) + 750 2 cos (X)(-cosx+1)+7 (-cosx+1)=0 COSXFO 2 cosx+7=0 X=0 10. sin 2x = cos X 11. sin x = COS X
1. For all x, the function f(x) = tan-',+ cot-1, has derivative f'(z)-12-17 0 1 +22 So f(x) must be a constant. a) What is that constant ? b) Explain by using a triangle c) What is limz+ */2-tan cot
Use trigonometric identities to solve the equation
2sin(2θ)-2cos(θ)=0 exactly for 0≤θ≤2π.
A.) What is 2sin(2θ) in terms of sin(θ)and cos(θ)?
B.) After making the substitution from part 1, what is the
common factor for the left side of the expression
2sin(2θ)-2cos(θ)=0 ?
C.) Choose the correctly factored expression from below.
a.)
b.)
c.)
d.)
We were unable to transcribe this imageAsin(e) cos(O) = 2cos(e) We were unable to transcribe this imageWe were unable to transcribe this image
Solve the separable initial value problem. tan(sin(x^(2) 1. y' = 2x cos(x2)(1 + y2), y(0) = 5 → y= 2. v' = 8e4x(1 + y2), y(0) = 2 + y=
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