In a normal distribution, the standard deviation is 20, what test score do you need to be in the top 2.5%? please help no mean is given if there was one i wouldn't ask
Answer)
As the data is normally distributed we can use standard normal z table to estimate the answers
Z = (x-mean)/s.d
Given s.d = 20
From z table, P(z>1.96) = 2.5%
So, z = 1.96
1.96 = (x - mean)/20
X = mean + 1.96*20
Or we can say that test score to be in top 2.5 is 1.96 standard deviation above the mean
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