Question

Suppose that on earth you can jump straight up a distance of 48 cm. Asteroids are made of material with mass density 2800 kg/m³. Part A What is the maximum diameter of a spherical asteroid from which you could escape by jumping? Express your answer with the appropriate units. HA Value Units dmax = Request Answer Submit

Answer 1

Here,

h= 48 cm = 48*10^-2 m

Then,

solution Houe, f = 2800 kg/m2 h : 48cm = 48x102m Then, The mass is; = m= sv .:: v= 4 TR3 put all values in equation, Em = 12800kg/m3)14 TR3) = m = 11728.61R3 Then, Using conserwation of energy is, & mv2 = mgh so, = v= 52gh = v= J 2x19-8m/s 3)(48X102m) = v= 3:07 mis Then, = v= 20m R .6= 6'67X10'' N.m2 | kg 2 = 3:07 m/s = 2x(667x10' N.m2/Kg2)(11728-61 R3) R. = 3.07 m/s - RS216-67x16") (1728.61 R3) = 3:07 m/s = (1.251x103)R = R = 3.07 m/s (1.251x1013) = R = 2:454X103 m

Then, The diameter is, = dimax = 2R so, = d max = 2 x (2-454X103 m) = d ma x = 4.908 x 103 m (Answer