Question

The boom OAB pivots about point o, while section AB simultaneously extends from within section OA. Determine the velocity and acceleration of the center of the pulley for the following conditions: 8 - 24,0 - 4 deg/sec, 0 - 2 deg/sec, 1 - 10ft, 1 - 2.5 ft/sec, 7 = -6.0 ft/sec? The quantities and 7 are the first and second time derivatives, respectively, of the length I of section AB. Express your answers as vectors in the e, and e, directions. 23 RE Answers eo) ft/sec e) ft/sec2

Answer 1

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Given Q=240 6 = 9 desee 4x (1 180) = 0.06991 noodl see = 2 del, 2 - 2x TT 180 = 0.09490 89dlies e = lot &= 25 Atlee = -6f4/2 - So, 8-23+10 = 33 ja 1=2.5 ftelsen je ľ- 6P132 Velocity vector y = rextroem y= 2.sert (33x0.06981) lo IV 2sert 2.30373 lo - Pt/sec

• Acceleration vector - 9= (s-r02) ert(rotard) ea - (-6-33(0.069812) ex + ( 33 (0.03490) +282.5)(0,06931) 9.-6. 1608 ert1.rooteo I 2