Test Statistic :-
t = -2.90
P - value = P ( t > 2.90 ) = 0.0029 ≈ 0.00
Decision based on P value
P - value = P ( t > 2.8972 ) = 0.0029
Reject null hypothesis if P value < α level of
significance
P - value = 0.0029 < 0.01 ,hence we reject null hypothesis
Conclusion :- Reject null hypothesis
Reject null hypothesis, sufficient evidence
Part b)
Confidence interval :-
DF = 44
t(α/2, DF) = t(0.01 /2, 44 ) = 2.692
Lower Limit =
Lower Limit = -23.03
Upper Limit =
Upper Limit = -0.85
99% Confidence interval is ( -23.03 , -0.85 )
Yes , only negative values.
Question 16: A study was done on proctored and nonproctored tests. The results are shown in...
A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. n Proctored Nonproctorec 12 31 30 75.98 86.26 10.57 19.42 X in a. Test the claim that students taking nonproctored tests get a higher...
Proctored Nonproctored ?2 30 84.06 A study was done on proctored and nonproctored tests. The results are shown in the table ssume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal Complete parts (a) and (b) below Use a 0 05 significance level for both parts X 77.73 s 11761883 a. Test the claim that students taking nonproctored tests get a higher mean score...
D Question 22 4 pts A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Use a 0.05 significance level. Test the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. Identify the null and alternative hypotheses Proctored Nonproctored Hi H2...
9.2 question 5 part b only explain how you find the confidence interval as well please!! Homework: 9.2-9.3 homework Save Score: 0.5 of 1 pt 5 of 15 (15 complete) HW Score: 57.81%, 8.67 of 15 pts 9.2.7-T Question Help Proctored Nonproctored A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple 11 H2 random samples selected from normally distributed populations, and do not assume that...
Question Help 9.2.7-T Assigned Media A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are Independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. I H2 31 8724 AE 33 77.93 4490 X <H-H2O (Round to two decimal places as needed.) Ji V...
A. B. C. D. Construct a confidence interval suitable for testing claim that students taking non proctored tests get higher mean score than those taking proctored tests. ___<µ1 - µ2 < ____ Yes/No____ because the confidence interval contains only positive values/only negative values/zero ______. E. Construct a confidence interval suitable for testing claim that students taking non proctored tests get higher mean score than those taking proctored tests. ___<µ1 - µ2 < ____ Yes/No____ because the confidence interval contains only...
u A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts Men 11 11 97.76°F 0.81°F Women 2 59 97.45°F 0.71°F S a. Test the claim that men have a higher mean...
A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts. n Treatment Placebo H2 34 40 2.39 2.62 0.56 0.85 X S UU. 110 H1 H2 H:H1 H2 UU. 110-11-12 HH1...
A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard n deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. H2 35 81.88 20.96 34 x 74.84 10.56 A study was done on proctored and nonproctored tests. The results are shown in the...
p-value too 5 of 11 (11 complete) core: 0.63 of 5 pts 39.2.7-1 HW Score: 57.05%, 31.38 of 55 pts Question Help P2 Proctored Nonproctored A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent i simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are n31 32 equal. Complete parts (a) and (b) below. Use a 0.05 significance...