Question

Fix My Screen is a local home TV repair service. They employ two repairmen who answer to all of the repair calls. The company sends Repairman D on 70 percent of all jobs, because the likelihood of a "second follow-up call" within a week is only 0.08 compared to 0.20 for Repairman K a. If you had a recent repair job that is going to require a second follow-up call, what is the probability 2. that Repairman K did your initial repair work? What is the probability that Repairman K will be sent on a second follow-up call for a job completed by Repairman D? What is the probability that Repairman D will be sent on a follow-up call to a job that he completed in the first place? b. c.

Answer 1

a. A second-follow up call within a a week implies that Repairman K was sent for the initial repair work.

70% of all first jobs are done by Repairman D so Probability = 0.7

so for K being sent prob = 1-0.7= 0.3

b. D completed the first job , so prob= 0.7

second follow up call , prob that K is being sent =0.20

so total prob in sequence= 0.7*0.2= 0.14

c. A job that has been completed implies D was sent on first prob= 0.7

Again he is sent prob = .08

so total prob = 0.08*0.7= 0.056