Find the value of A and show work In(k) = In(A) + -E2(RT) k=0.00235 [a=-39.97 kJ...
Determine K for a reaction at 200 K if AG° = 12.9 kJ/mol. (R = 8.314 J/mol · K)
What is the value of Keq if ∆Gº=15.6 kJ (R=8.314 J/mol-K)? 1.84x10-3 0.994 1.01 5.05x10-7
Can you show the work for these problems?
Ethanol has an enthalpy of vaporization of 42.3 kJ/mol. The compound has a vapor pressure of 1.00 atm at 78.3 degree C. At what temperature is the vapor pressure equal to 0.800 atm? (R = 8.314 J/K middot mol) -83.8 degree C -24.4 degree C 62.6 degree C 73.0 degree C 78.0 degree C A liquid has an enthalpy of vaporization of 30.4 kJ/mol. At 269 K is has a vapor pressure...
Determine K for a reaction at 200 Kif AG° = 27.8 kJ/mol. (R = 8.314 J/mol · K)
2. The evaporation enthalpy for a liquid is AH- 52 kJ/mol and the saturation vapor pressure at t-10°C is Psat-0.23 kPa. Find the saturation pressure at t 15°C. The gas constant is R- 8.314 J mol K
Useful Information: Please show your work and write in complete sentences. R= 8.314 J/mol K 1/[A].= kt +1/[A]. In k=-E/RT+ In A In [A] =-kt + In[A]. In kı/k2 = E/R (1/T2 - 1/11) 1. The following data were collected for the reaction: 2 C102(aq) + 2 OH (g) → C103 (aq) + ClO2 (aq) + H2O(1) Experiment [C102], M [OH-], M Initial Rate, M/s 1 0.060 0.030 0.0248 2 0 .020 0.030 0.00276 0.020 0 .090 0.00828 a. Determine...
AG RT In = RT In Q- RT In K When the system is at equilibrium Q=1 and thus lIn 1-0, so then we can use this equation AG =-RT In K to find the temperature (solve for T). Remember T will be in K. Once we have the temperature we then use the following equation to calculate AG AG= AG+ RT In Q These molecular scenes represent three mixtures in which A2 (black) and B2 (green) are forming AB....
In this lab, you will determine the vapour pressure of ethanol (P) at various temperatures and use this data to find the enthalpy of vaporization (ΔvapH). If a plot of ln P vs. 1/T gives a slope of -9782 K, what is the ΔvapH in kJ/mol? Do not worry about how realistic the value is. Assume R = 8.314 J mol-1 K-1.
The activation energy, Ea, for a particular reaction is 19.4 kJ/mol. If the rate constant at 80 °C is 0.820 M⁻¹s⁻¹, then what is the value of the rate constant at 209 °C? (R = 8.314 J/mol • K)
The activation energy, Ea, for a particular reaction is 19.4 kJ/mol. If the rate constant at 80 °C is 0.820 M⁻¹s⁻¹, then what is the value of the rate constant at 121 °C? (R = 8.314 J/mol • K)