Determine K for a reaction at 200 Kif AG° = 27.8 kJ/mol. (R = 8.314 J/mol...

Question

Question

Determine K for a reaction at 200 Kif AG° = 27.8 kJ/mol. (R = 8.314 J/mol · K)

Answer 1

Answer #1

Given,

temperature =200 K

Gibbs free energy change ( $\Delta$ G) = 27.8 kJ/mol = 27800 J/mol

ideal gas constant = 8.314 J/mol

relation between gibbs free energy change and equillibrium(K) constant is given as

$\Delta$ G = -RT ln K

27800 = - 8.314x200 lnK

ln K = - 16.71

taking antiln both sides

K= 5.62 x 10^-8

Answer 2

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