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Determine AGⓇ for a reaction when AG = -184.7 kJ/mol and Q = 0.043 at 298...
Determine Gº for a reaction when AG = -119.1 kJ/mol and Q = 0.043 at 298 K. (R = 8.314 J/mol · K)
() Calculate AGⓇ for the following reaction at 298 K. The AGP values are 0 kJ/mol for C12(e) -325 kJ/mol for Cisce), and -286 kJ/mol for PC13(e). PC1518) PC3(8) + Cl2(g) (b) Calculate AG at 298 K for the reaction if the partial pressures are PC120,40 atm, PPC13 -0.27 atm, and PPCi5 -0.0029 atm.
Determine K for a reaction at 200 K if AG° = 12.9 kJ/mol. (R = 8.314 J/mol · K)
Determine K for a reaction at 200 Kif AG° = 27.8 kJ/mol. (R = 8.314 J/mol · K)
For a particular reaction, AH = -14.20 kJ/mol and AS = -198.5 J/(mol.K). Calculate AG for this reaction at 298 K. AG = 73.35 kJ/mol
Use Hess' law and the data below to calculate AG, in kJ, for the following reaction: NO(g) + O (9) NO2 (g), AG° = ? 2 03 (9) - 3 O2 (g), AG° = +489.6 kJ 02 (9) 20 (9), AGⓇ = +463.4 kJ NO(g) + O2 (9) - NO2 (g) + O2 (g), AG° = -199.5 kJ QUESTION 14 Calculate AG for the following reaction, in kJ, at 0 °C under the following non-standard conditions shown below. 2 Hgo...
HELP PLEASE (a) Calculate AGⓇ for the following reaction at 298 K. The AGP values are 0 kJ/mol for Cl2(e) -325 kJ/mol for PC (e), and -286 kJ/mol for PC13(e). PCIE) - PC3(g) + Cl2(8) (6) Calculate AG at 298 K for the reaction if the partial pressures are PC12 -0.40 atm, PPC13 - 0.27 atm, and PPCIS -0.0029 atm.
For a particular reaction at 203.3 °C, AG = 424.99 kJ/mol, and AS - 551.38 J/mol K). Calculate AG for this reaction at -66.6 °C. AG = kJ/mol What is the value of K for this aqueous reaction at 298 K? A + B =C+D AG° = 11.80 kJ/mol
Using provided data, determine AG* (in kJ) for the following reaction. 2036) ++3026) AH,(kJ/mol) S /mol) Ozle) 205.0 Ole) 143 238.82 Question 11 2 pts Use the provided information to determine the equilibrium constant at 298 K for the reaction given 2NO26) N204(8) 4 AH® (kJ/mol) 5° (J/molk) NO2(g) 33.2 239.9 N2048) 9.16 304.3 Equilibrium Constant - (Select) x 10 (Select)
31. What is ∆G for a reaction where ∆G° = -4.5 kJ/mol and Q = 4.0 at 295 K? (R = 8.314 J/mol ・ K)