10. The formula for finding ∆G° is ∆G° = ∆H° - T∆S° where ∆H° is the difference in enthalpy of formation of product and reactant. ∆S° is the difference in entropy of product and reactant.
∆H° = 0 - 2*143 =-286 kJ
∆S° = 3*205 - 2*238.82 = 137.36 J/K = 0.137 kJ/K
Standard temperature = 298 K
∆G = -286 kJ - (298K) * (0.137 kJ/K) = -326.8 kJ
Answer : -326.8 kJ
Using provided data, determine AG* (in kJ) for the following reaction. 2036) ++3026) AH,(kJ/mol) S /mol)...
Question 20 1 pts Using provided data, determine AGº (kJ) for the following reaction. 2Fe(s) + 3C12(8) 2FeCl3(s) AH® (kJ/mol) S (J/molk) Fe(s) 27.3 Cl2le) 223.0 FeCl3(s) -399.5 142 Question 21 1 pts Determine AG (in kJ) for the following reaction at 325K when the concentrations of the species are as follows: NO, - 10.00 M, N204 - 11.1 M. AGº (NO) - 51 kJ/mol, AG (N204) - 97.7 kJ/mol 2NO26) N20 (8)
D Question 21 1 pts Determine AG (in kJ) for the following reaction at 325K when the concentrations of the species are as follows: NO2 - 10.00 M, N,04 - 18.3M. AG* + (NO2) - 51 kJ/mol, AG®(N204) - 97.7 kJ/mol 2NO26) > N2O4(s)
Nitrogen AHºf (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) N2 (g) 0 0 191.6 472.7 455.6 153.3 N(g) NH3 (g) -46.1 -16.5 192.5 NH3 (aq) -80.0 -27.0 111.0 NH4+ (aq) -132.0 -79.0 113.0 NO (g) 90.3 86.6 210.8 NOCI (g) 51.7 66.1 261.8 NO2 (g) 33.2 51.3 240.1 N20 (g) 82.1 104.2 219.9 N204 (8) 9.2 97.9 304.3 Consider the reaction N2(9) + 202(9)—2NO2(g) Using the standard thermodynamic data in the tables linked above, calculate Grxn for this reaction at 298.15K...
D Question 21 1 pts Determine AG (in kJ) for the following reaction at 325K when the concentrations of the species are as follows: NO2 = 10.00 M, N204 - 11.1 M. AG° F (NO2) = 51 kJ/mol, AG°(N2O4) = 97.7 kJ/mol 2NO2(g) +N204(8)
For a particular reaction, AH = -14.20 kJ/mol and AS = -198.5 J/(mol.K). Calculate AG for this reaction at 298 K. AG = 73.35 kJ/mol
7 Consider the following reaction at 298 K: NH3(g) +HCI(g)NH4CI(s) Using the thermochemical data at 298 K given below (a) Determine the AH for the reaction. (2 marks) (b) Determine the AG for the reaction and comment on its value. (3 marks) (c) Determine the maximum work done available in the reaction. (3 marks) An equilibrium mixture, consisting of 0.5 atm of NHy(), 0.5 atm of HCKg) and excessive of NH Cl(s), is enclosed in a container at 298 K...
12. Consider the following data and calculate AG°, in kJ, at 155°C for the following reaction. 2 03(g) + 3 O2(g) A: DH - TAS AH® (kJ/mol) 142.7) 2 0 Sº (J/mol K) 238.8) 2 205.0 2854-428.15 A) -344.2 B)-306.7 C)-2.16 x 104 D)-5.91 x 104 E) none of these
5. The equilibrium constant K for the dissociation of N204(g) to NO2(g) is 1700 at 500 K. If AH is 56.8 kJ/mol for this reaction, what will be the value of K at 300 K? (a) 132x106 (b) 1.11 x 104 (c) 0.188 (d) 15.5 (e) .54 x 107 5. The equilibrium constant K for the dissociation of N204(g) to NO2(g) is 1700 at 500 K. If AH is 56.8 kJ/mol for this reaction, what will be the value of...
D Question 20 1 pts Using provided data, determine AGⓇ (kJ) for the following reaction. 2Fe(s) + 3C12() <2FeCl3(s) AH, (kJ/mol) S (J/molk) Fe(s) 27.3 Cl2(e) 223.0 FeCl3(s) -399.5 142