We want to determine the AOQ for an acceptance sampling plan when the quality of the incoming lots in percent defective is 4%, and then again when the incoming percent defective is 8.5%. The sample size is 50 units for a lot size of 600 units. Furthermore, Pa at 4% defective levels is 0.89. At 8.5% incoming defective levels, the Pa is found to be 0.59. Determine the average outgoing quality for both incoming percent defective levels.
The average outgoing quality for 4% incoming percent defective level is __ (Round your response to three decimal places.)
The average outgoing quality for 8.5% incoming percent defective level is __. (Round your response to three decimal places.)
The average outgoing quality for 4% incoming percent defective level is 0.033
The average outgoing quality for 8.5% incoming percent defective level is 0.046
Explanation:
Average outgoing quality or AOQ for percent defective= (Pd)(Pa)(N-n)/N
Pd= true percent defective of the lot = 4%= 0.04
Pa = probability of accepting the lot = 0.89
N= number of items in the lot = 600
n= number of items in the sample= 50
Hence AOQ = 0.04*0.89*(600-50)/600 = 0.033
When Pd = 8.5%= 0.085 and Pa = 0.59,
AOQ = 0.085*0.59*(600-50)/600 = 0.046
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