Question

b. Write the cell notation for the following redox reaction. Here, Cu⁺ or CuNO₃ is oxidized to Cu²⁺ or Cu(NO₃)₂in the oxidation half-cell. Since there is only aqueous species and there is no electrode (metal) in the oxidation half-cell, use platinum (Pt) as an inert electrode in the oxidation half-cell.

3CuNO₃(aq) + Au(NO₃)₃(aq) ⟶ 3Cu(NO₃)₂(aq) + Au(s)                   

Answer 1

The reaction giveny 3 eu NO₂ (aq) + Au (NO₃)₂ (aq) 3 Cu(NO₃)2 (ar) + Auls) we can write ionically zeut cour) & Ahat can edun 27 (aq) + Auls) L oxidation - 1 oxidation halb eelison 3 eut (as) Cu2+ +30 - 0 x3 reduction hall, celloon Aust(49) + 3e Auls) --- 9 overall rxn zeut (aa) + Au3 can) 3 eu 2 lag) + Auls) So, cell notation is, - Phis, cut cars / cu 2 (aq) | Austcan) [Au(s) in ionie form PAIS), EU NO3(aq) | Cu(NO3), las | Au(NO3)2 (aa) | Auls)