Question

**THIS IS A Z TEST**

PLEASE USE EXCEL OR STATISTICS SOFTWARE, NO HANDWRITTEN ANSWERS. THANK YOU!

An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 98 type K batteries and a sample of 92 type Q batteries. The mean voltage is measured as 9.32 for the type K batteries with a standard deviation of 0.258, and the mean voltage is 9.62 for type Q batteries with a standard deviation of 0.189. Conduct a hypothesis test for the conjecture that the mean voltage for these two types of batteries is different. Step 1 of 4: State the null and alternative hypotheses for the test. EE TablesKeypad Answer 2 Points Ho:H1

Answer 1

From the given information

The following null and alternative hypotheses need to be tested: This corresponds to a two-tailed test, for which a z-test for two population means, with known population standard deviations will be used. Based on the information provided, the significance level is α 0.02, and the critical value for a two- tailed test is z 2.33 The rejection region for this two-tailed test is R-{: > 2.33) (3 The z-statistic is computed as follows: 9.32-9.62 V0.2582/98 +0.1892/92 -9.182 ▼ V01/nitơ./n2 (4) Decision about the null hypothesis Since it is observed that9.1822.33, it is then concluded that the null hypothesis is rejected. Using the P-value approach: The p-value is p 0, and since p0.02, it is concluded that the null hypothesis is rejected