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Find the solution of the initial value problem y(1) = 46 y = sqrt(e^(-1/x+2)+5) Your answer...
Problem #2: Let y(x) be the solution to the following initial value problem. x4 y' +...
Problem #2: Let y(x) be the solution to the following initial value problem. x4 y' + 5x> y = Inça), x>0, y(1) = 5. Find y(e). Problem #2: O Problem #2: Enter your answer symbolically, as in these examples Just Save Submit Problem #2 for Grading Problem #2 | Attempt #1 | Attempt #2 | Attempt #3 Your Answer: Your Mark:
Find the solution of the initial value problem (x In x) y'+y = 2 In x,...
Find the solution of the initial value problem (x In x) y'+y = 2 In x, yle) = 1. 1 y(x) = 1 + In Inr 1 y(x) = Inca Inr y(x) = e + Inc e In 2 y(x) = Inc (2) = el-r
Find the solution y of the initial value problem 3"(t) = 2 (3(t). y(1) = 0,...
Find the solution y of the initial value problem 3"(t) = 2 (3(t). y(1) = 0, y' (1) = 1. +3 g(t) = M Solve the initial value problem g(t) g” (t) + 50g (+)? = 0, y(0) = 1, y'(0) = 7. g(t) = Σ Use the reduction order method to find a second solution ya to the differential equation ty" + 12ty' +28 y = 0. knowing that the function yı(t) = + 4 is solution to that...
3. (20 points) Find the solution y = y(x) of the initial value problem y 0...
3. (20 points) Find the solution y = y(x) of the initial value
problem y 0 − y x = cos2 (y/x) , y(1) = π 3
3. (20 points) Find the solution y = y(x) of the initial value problem 37 - = cos”(y/2),y(1) = 5
x Your answer is incorrect. Try again. Find the solution of the given initial value problem....
x Your answer is incorrect. Try again. Find the solution of the given initial value problem. y(4) - 12y" + 367" = 0 y(1) = 10 + e, y' (1) = 7+6eº, y" (1) = 36e", y" (1) = 216e y(t) = 2+7x+e^(6x) Tau Click if you would like to Show Work for this question: Open Show Work
Let y(x) be the solution to the following initial value problem. dy dx In x =...
Let y(x) be the solution to the following initial value problem. dy dx In x = -2 xy y(1) = 4 Find y(e). Enter your answer symbolically, as in these examples
Find the solution of the initial value problem y′′+7y′+10y=0, y(0)=11 and y′(0)=−46.
Find the solution of the initial value problem y′′+7y′+10y=0, y(0)=11 and y′(0)=−46.
Solve the initial value problem y' = 2(sec2x) * sqrt(y) where y(pi/4) = 0 Keep answer...
Solve the initial value problem y' = 2(sec2x) * sqrt(y) where y(pi/4) = 0 Keep answer in terms of trig functions.
1. Find the particular solution of the differential equation dydx+ycos(x)=2cos(x)dydx+ycos(x)=2cos(x) satisfying the initial condition y(0)=4y(0)=4. 2. Solve...
1. Find the particular solution of the differential
equation
dydx+ycos(x)=2cos(x)dydx+ycos(x)=2cos(x)
satisfying the initial condition y(0)=4y(0)=4.
2. Solve the following initial value problem:
8dydt+y=32t8dydt+y=32t
with y(0)=6.y(0)=6.
(1 point) Find the particular solution of the differential equation dy + y cos(x) = 2 cos(z) satisfying the initial condition y(0) = 4. Answer: y= 2+2e^(-sin(x)) Your answer should be a function of x. (1 point) Solve the following initial value problem: dy ty 8 at +y= 32t with y(0) = 6. (Find y as...
part c Solve the initial value problem yy' + + y with y(4) - 33 a....
part c
Solve the initial value problem yy' + + y with y(4) - 33 a. To solve this, we should use the substitution u=x^2+y^2 help (formulas '= 2x+2yi help (formulas) Enter derivatives using prime notation (e.g.. you would enter y' for ). N b . After the substitution from the previous part, we obtain the following linear differential equation in ruu 1/2 sqrt() help. (equations e. The solution to the original initial value problem is described by the following...
Problem #2: Let y(x) be the solution to the following initial value problem. x4 y' + 5x> y = Inça), x>0, y(1) = 5. Find y(e). Problem #2: O Problem #2: Enter your answer symbolically, as in these examples Just Save Submit Problem #2 for Grading Problem #2 | Attempt #1 | Attempt #2 | Attempt #3 Your Answer: Your Mark:
Find the solution of the initial value problem (x In x) y'+y = 2 In x, yle) = 1. 1 y(x) = 1 + In Inr 1 y(x) = Inca Inr y(x) = e + Inc e In 2 y(x) = Inc (2) = el-r
Find the solution y of the initial value problem 3"(t) = 2 (3(t). y(1) = 0, y' (1) = 1. +3 g(t) = M Solve the initial value problem g(t) g” (t) + 50g (+)? = 0, y(0) = 1, y'(0) = 7. g(t) = Σ Use the reduction order method to find a second solution ya to the differential equation ty" + 12ty' +28 y = 0. knowing that the function yı(t) = + 4 is solution to that...
3. (20 points) Find the solution y = y(x) of the initial value
problem y 0 − y x = cos2 (y/x) , y(1) = π 3
3. (20 points) Find the solution y = y(x) of the initial value problem 37 - = cos”(y/2),y(1) = 5
x Your answer is incorrect. Try again. Find the solution of the given initial value problem. y(4) - 12y" + 367" = 0 y(1) = 10 + e, y' (1) = 7+6eº, y" (1) = 36e", y" (1) = 216e y(t) = 2+7x+e^(6x) Tau Click if you would like to Show Work for this question: Open Show Work
Let y(x) be the solution to the following initial value problem. dy dx In x = -2 xy y(1) = 4 Find y(e). Enter your answer symbolically, as in these examples
1. Find the particular solution of the differential
equation
dydx+ycos(x)=2cos(x)dydx+ycos(x)=2cos(x)
satisfying the initial condition y(0)=4y(0)=4.
2. Solve the following initial value problem:
8dydt+y=32t8dydt+y=32t
with y(0)=6.y(0)=6.
(1 point) Find the particular solution of the differential equation dy + y cos(x) = 2 cos(z) satisfying the initial condition y(0) = 4. Answer: y= 2+2e^(-sin(x)) Your answer should be a function of x. (1 point) Solve the following initial value problem: dy ty 8 at +y= 32t with y(0) = 6. (Find y as...
part c
Solve the initial value problem yy' + + y with y(4) - 33 a. To solve this, we should use the substitution u=x^2+y^2 help (formulas '= 2x+2yi help (formulas) Enter derivatives using prime notation (e.g.. you would enter y' for ). N b . After the substitution from the previous part, we obtain the following linear differential equation in ruu 1/2 sqrt() help. (equations e. The solution to the original initial value problem is described by the following...
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