Let A be a 3 x 3 matrix with the following property: 2 times the 1st column minus 3 times the 2nd column equals the 3rd column. Find all nontrivial solutions of Ax = 0 without row reduction. Describe the geometry of the solution set.
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Given A and b to the right, write the augmented matrix for the linear system that corresponds to the matrix equation Axequals=b. Then solve the system and write the solution as a vector. Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 3 3rd Column negative 2 2nd Row 1st Column negative 2 2nd Column negative 2 3rd Column 0 3rd Row 1st Column 5 2nd Column 2 3rd Column 6 EndMatrix right bracket 1...
i need help with these two questions. it is from linear algebra Describe the possible echelon forms of the following matrix. A is a 2x2 matrix with linearly dependent columns. Select all that apply. (Note that leading entries marked with an X may have any nonzero value and starred entries may have any value including zero.) A. Х * B. 0 X 0 0 0 X C. х * D. 0 0 0 0 0 1 5 4 -5 -8...
If a dealer's profit, in units of $30003000, on a new automobile can be looked upon as a random variable X having the density function below, find the average profit per automobile. f(x) equals= left brace Start 2 By 2 Matrix 1st Row 1st Column StartFraction 1 Over 22 EndFraction left parenthesis 12 minus x right parenthesis comma 2nd Column 0 less than x less than 2 comma 2nd Row 1st Column 0 comma 2nd Column elsewhere EndMatrix 122(12−x), 0<x<2,...
Let A be an nx n matrix. Select all of the following that are equivalent to the statement: A is invertible. The homogeneous equation Ax-0 has a nontrivial solution. The echelon form of A has a pivot in every row and every column. The columns of A are linearly dependent For any vector b in R", Ax-b has a unique solution. The linear transformation x Ax is 1-1 and onto. A is nonsingular.
Let A = and b = . Show that the equation Ax = b does not have a solution for some choices of b, and describe the set of all b for which Ax = b does have a solution. How can it be shown that the equation Ax = b does not have a solution for some choices of b? A. Row reduce the augmented matrix [A b] to demonstrate that [A b] has a pivot position in every row B. Find a vector...
i need help with the last part on each question. I am not understanding because I keep getting those parts incorrect. this is linear algebra 4-3 1 3 Given A and b to the right, write the augmented matrix for the linear system that corresponds to the matrix equation Ax b Then solve the system and write the solution as a vector A = 1 2 3 17 -4 -2 2 18 Write the augmented matrix for the linear system...
Determine ModifyingBelow lim With x right arrow c Superscript plusf(x), ModifyingBelow lim With x right arrow c Superscript minusf(x), and ModifyingBelow lim With x right arrow cf(x), if it exists. cequals3, f(x)equals left brace Start 2 By 2 Matrix 1st Row 1st Column 4 minus x 2nd Column x less than 3 2nd Row 1st Column StartFraction x Over 3 EndFraction plus 1 2nd Column x greater than 3 EndMatrix ModifyingBelow lim With x right arrow c Superscript plusf(x)equals nothing...
b. - 2 -1 1 and b Let A = Show that the equation Ax =b does not have a solution for all possible b, and -3 0 3 4-2 2 b3 describe the set of all b for which Ax b does have a solution How can it be shown that the equation Ax = b does not have a solution for all possible b? Choose the correct answer below. O A. Find a vector b for which the...
Determine ModifyingBelow lim With x right arrow c Superscript pluslimx→c+f(x), ModifyingBelow lim With x right arrow c Superscript minuslimx→c−f(x), and ModifyingBelow lim With x right arrow climx→cf(x), if it exists. cequals=22, f(x)equals= left brace Start 2 By 2 Matrix 1st Row 1st Column 3 minus x 2nd Column x less than 2 2nd Row 1st Column StartFraction x Over 2 EndFraction plus 1 2nd Column x greater than 2 EndMatrix 3−x x<2 x2+1 x>2
1-4 - 31 Let A= 3 and b= Show that the equation Ax=b does not have a solution for all possible b, and describe the set 4 26 of all b for which Ax=b does have a solution. How can it be shown that the equation Ax = b does not have a solution for all possible b? Choose the correct answer below. O A. Row reduce the augmented matrix [ a b ] to demonstrate thatſ A b )...