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Use the classes given in the previous question and write the output tha t is generated when this program is run. You may writ


public class George extends Elaine {! public void method1() { System.out.print(George 1 ); public class Jerry { public void
public void method20 { System.out.print(Jerry 2 ); public String toString() { return Jerry; public class Elaine extends K
public class Kramer extends Jerry { public void method1() { super.methodi; System.out.print(Kramer 1 ); public void method2
public String toString() { return Kramer;
UPO ! Jerry() seinfeld - { new George(), new Kramer(), new Jerry0, new Elain e) }; for (int i = 0; i < seinfeld.length; i++)
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Answer #1

The heirarchy is as below:

Jerry (Base class) <- Kramer <- Elaine <- George

So, George is grand grand child of Jerry.. in the code we are trying to manually typecase a Kramer object into a George object, which is not allowed. A child object can be typecasted to its parent object, since parent references can hold child object, but not the other way round..

hence it is a runtime error. Since we are typecasting explicitly, hence there will be no compile time error.

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