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Answer: here is the answer for your code:
CODE SNIPPET:
OUTPUT:
so 20 is the right answer
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Consider the following code. It is valid. What is printed? public static void TestLabel() { int...
What will the code shown below print to the console? public class Cascade public static void...
What will the code shown below print to the console? public class Cascade public static void print(int arg){ for(int i=0; i<arg; i++){ System.out.print(""); } System.out.println(""); if(arg > 1){ print(arg-1); } } public static void main(String[] args) { print(4); } } E B IV AA- IES XX, SE V GT 12pt Paragraph -
Given: public class RunMethodExample2 { public void run() { for(int i=1;i<=3;i++) { try{ Thread.sleep(1000); catch(InterruptedException ie)...
Given: public class RunMethodExample2 { public void run() { for(int i=1;i<=3;i++) { try{ Thread.sleep(1000); catch(InterruptedException ie) { ie.printStackTrace(); System.out.println(i); public static void main(String args[]) { Thread th1 = new Thread(new RunMethodExample(), "th1"); Thread th2 = new Thread(new RunMethodExample(), "th2"); th1.run(); th2.run(); Why could the output NOT be the following?
on 2 Consider the following recursive method test: public static int test(String s, int last) if...
on 2 Consider the following recursive method test: public static int test(String s, int last) if (last < 0) { return 0; if (s.charAt(last) == 0) { return 2 - test(s, last - 1); return 1 + 2 test(s, last - 1); What is the output of: test("11001", 4). TTT Arial 3 (12pt) - TEE 25
5. What is the Big Oh method m2? public static void m2(int[] arr, int n) for...
5. What is the Big Oh method m2? public static void m2(int[] arr, int n) for (int í = 1; í <= n- 1; i++) pM2(arr [i], arr, 0, i - 1); // end m2 private static void pM2(int entry, int[l arr, int begin, int end) int i- end; for(; (i 〉= begin) && (entry 〈 arr [i]); i--) arr [1 + 1] = arr L1] arr[i + 1] - entry; return // end pM2
What is printed by running the following code? public static void main(String[] args) { int[] nums...
What is printed by running the following code? public static void main(String[] args) { int[] nums = {2, 3, 4}; int n = 5; changeMe1(n, nums); System.out.print( n ); System.out.print(nums[0]); changeMe2(n, nums); System.out.print( n ); System.out.print(nums[0]); } public static void changeMe1(int number, int[] list) { number++; list[0]++; } public static void changeMe2(int number, int[] list) { number = 9; list = new int[1]; list[0] = 99; }
Consider the following method. public static ArrayList<Integer mystery(int n) ArrayList<Integer seg - new ArrayList<IntegerO; for (int...
Consider the following method. public static ArrayList<Integer mystery(int n) ArrayList<Integer seg - new ArrayList<IntegerO; for (int k = n; k > 0; k--) seq.add(new Integer(k+3)); return seq What is the final output of the following Java statement? System.out.println(mystery(3)); a. [1,2,4,5) b. [2,3,4,5) c. [6,5,4,3] d. [7, 7, 8, 8] e. [7,8,9, 8) O Consider the following method: public static int mystery(int[] arr, int k) ifk-0) return 0; }else{ return arr[k - 1] + mystery(arr, k-1):) The code segment below is...
Consider the following method: Linel: public static int mystery(int n) { Line2: if (n < 10)...
Consider the following method: Linel: public static int mystery(int n) { Line2: if (n < 10) { ine3: return n; Line4: } else { Line5: int a = n/10; Line 6: int b = n % 10; Line 7: return mystery(a + b); Line 8: } Line 9: } What is the result of the following call? System.out.println(mystery(648)); 18 8 12
What is printed when the following code is executed? #include <stdio.h> int main() { for (int...
What is printed when the following code is executed? #include <stdio.h> int main() { for (int i=3, j=5; i>=0; i-=2, j+=j*i) { printf("%d", j); منم }
**JAVA*JAVA Question 1 How many k's values will be printed out? public static void main(Stringl args)...
**JAVA*JAVA Question 1 How many k's values will be printed out? public static void main(Stringl args) for (int k-1: k10:k if (k8) continue: System.out.println k) Question 2 3.5 pts Analyze the following code. Which one is correct? package p public class A package p2: import p1. public class B extends Af int i- 5 private int j- 10: public A0I public static void main(Stringll args) B b new B0: System.out.println(a.i+", "+ajt", "+b.it""+bj): a.i is printable None of them b.i is...
What is the time and space complexity of this code with explanation? public static int getv(int...
What is the time and space complexity of this code with
explanation?
public static int getv(int num, List<Integer> rating, int target) { int count 0; HashMap<Integer, Integer> map = new HashMap<>(); for(int i = 0; i < num; i++){ if(!map.containsKey(rating.get(i))){ map.put(rating.-get(i), 0); } map.put(rating.get(i), map.get(rating.get(i))+1); } for(int i = 0; i < num; i++){ if(map.get(target -rating.get(i)) != null){ count += map.get(target-rating.get(i)); } if(target-rating.get(i) == rating.get(i)){ count--; } return count/2; }
What will the code shown below print to the console? public class Cascade public static void print(int arg){ for(int i=0; i<arg; i++){ System.out.print(""); } System.out.println(""); if(arg > 1){ print(arg-1); } } public static void main(String[] args) { print(4); } } E B IV AA- IES XX, SE V GT 12pt Paragraph -
Given: public class RunMethodExample2 { public void run() { for(int i=1;i<=3;i++) { try{ Thread.sleep(1000); catch(InterruptedException ie) { ie.printStackTrace(); System.out.println(i); public static void main(String args[]) { Thread th1 = new Thread(new RunMethodExample(), "th1"); Thread th2 = new Thread(new RunMethodExample(), "th2"); th1.run(); th2.run(); Why could the output NOT be the following?
on 2 Consider the following recursive method test: public static int test(String s, int last) if (last < 0) { return 0; if (s.charAt(last) == 0) { return 2 - test(s, last - 1); return 1 + 2 test(s, last - 1); What is the output of: test("11001", 4). TTT Arial 3 (12pt) - TEE 25
5. What is the Big Oh method m2? public static void m2(int[] arr, int n) for (int í = 1; í <= n- 1; i++) pM2(arr [i], arr, 0, i - 1); // end m2 private static void pM2(int entry, int[l arr, int begin, int end) int i- end; for(; (i 〉= begin) && (entry 〈 arr [i]); i--) arr [1 + 1] = arr L1] arr[i + 1] - entry; return // end pM2
Consider the following method. public static ArrayList<Integer mystery(int n) ArrayList<Integer seg - new ArrayList<IntegerO; for (int k = n; k > 0; k--) seq.add(new Integer(k+3)); return seq What is the final output of the following Java statement? System.out.println(mystery(3)); a. [1,2,4,5) b. [2,3,4,5) c. [6,5,4,3] d. [7, 7, 8, 8] e. [7,8,9, 8) O Consider the following method: public static int mystery(int[] arr, int k) ifk-0) return 0; }else{ return arr[k - 1] + mystery(arr, k-1):) The code segment below is...
Consider the following method: Linel: public static int mystery(int n) { Line2: if (n < 10) { ine3: return n; Line4: } else { Line5: int a = n/10; Line 6: int b = n % 10; Line 7: return mystery(a + b); Line 8: } Line 9: } What is the result of the following call? System.out.println(mystery(648)); 18 8 12
What is printed when the following code is executed? #include <stdio.h> int main() { for (int i=3, j=5; i>=0; i-=2, j+=j*i) { printf("%d", j); منم }
**JAVA*JAVA Question 1 How many k's values will be printed out? public static void main(Stringl args) for (int k-1: k10:k if (k8) continue: System.out.println k) Question 2 3.5 pts Analyze the following code. Which one is correct? package p public class A package p2: import p1. public class B extends Af int i- 5 private int j- 10: public A0I public static void main(Stringll args) B b new B0: System.out.println(a.i+", "+ajt", "+b.it""+bj): a.i is printable None of them b.i is...
What is the time and space complexity of this code with
explanation?
public static int getv(int num, List<Integer> rating, int target) { int count 0; HashMap<Integer, Integer> map = new HashMap<>(); for(int i = 0; i < num; i++){ if(!map.containsKey(rating.get(i))){ map.put(rating.-get(i), 0); } map.put(rating.get(i), map.get(rating.get(i))+1); } for(int i = 0; i < num; i++){ if(map.get(target -rating.get(i)) != null){ count += map.get(target-rating.get(i)); } if(target-rating.get(i) == rating.get(i)){ count--; } return count/2; }
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