Homework Answers
(c)
Given
Efficiency =50%
Tc = 40 °F
Tc in Kelvin can be converted by following formula
Tc =(°F+459.67)* 5/9
Tc =(40+459.67)*5/9
Tc = 277.6 K
Now efficiency of reversible engine
Efficiency = 1-Tc/Th
0.50=1-277.6/Th
Th =555.2 k
Again converting kelvKe to ferehnite
Using above formula
Th =539.7 °F
(D)
Th in Kelvin
Th = 727+273 = 1000 K
Efficiency of reversible engine
Efficiency = (1-Tc/Th)
0.40= (1-Tc/1000)
Tc = 600 k
Now Tc in celcius
Tc=600-273
Tc=327°C
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I only need C and D please!
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